Let A represent the value of the car after each year.
A= initial value (P)×(1+percent increase(r)) ^time
A=P×(1+r)^t
A=18710×(1+(-12%))^8
A=18710×(1-12%)^8
A=18710×(1-0.12)^8
A=18710×(0.88)^8
A= 6728.7619591115
The best approximation is 6729
Therefore the value of the car will be about $6729 after 8 years
Your answer is B.
Answer:
hope it helps man
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Step-by-step explanation:
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Answer: 2.66 × 10⁻¹³
<u>Step-by-step explanation:</u>
First, use the decay formula
where
- A is the final amount (amount left)
- A₀ is the initial amount (amount you started with)
- k is the rate of decay (you need to solve for this)
- t is the time
Given:
- A = 1/2(300) = 150
- A₀ = 300
- k = unknown
- t = 28.8

Next, input the k-value and the new t-value to solve for A.
- A = unknown
- A₀ = 300
- k = -0.0240676
- t = 1440
