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rusak2 [61]
3 years ago
7

Find the approximate area of a semi circle with a radius of 6 cm

Mathematics
1 answer:
Trava [24]3 years ago
3 0

113.04  es la respuesta, ya que para sacar el area es Pi por el radio al cuadrado osea 3.14 por 36, denada

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54 blue marbles 24 red marbles and 18 yellow marbles arranged in equal groups
vampirchik [111]
Divide each by their GCF
4 0
3 years ago
Read 2 more answers
Need help ASAP <br> I dont know what to do please help
shusha [124]

Answer:

the first option

Step-by-step explanation:

equilateral triangles are also equiangular which means each of the three angles is 60°

but you can have an acute triangle with angle measures that are all acute (for example, 59°, 85°, and 36°) that is not equilateral

8 0
3 years ago
What is the range of function gif g(x) = -2/(x) + 1
Zina [86]

The function g(x) is a rational function, and none of the options represent the range of the function g(x)

<h3>How to determine the range of the function?</h3>

The function is given as:

g(x) = -2/x + 1

The above function is undefined at point x = 0.

This is so because -2/x is undefined.

So, we have:

g(0) = -undefined + 1

g(0) = undefined

This means that the range of the function is:

(-infinity, 1) and (1, infinity)

None of the options represent the range of the function g(x)

Read more about range at:

brainly.com/question/10197594

#SPJ1

5 0
2 years ago
Too stoned help pls
podryga [215]
Distributive proeprty
wait
combein elike terms
4(1m+3+5m)=4(5m+1m+3)=4(6m+3)

if we distribute
reemmber that a(b+c)=ab+ac
4(6m+3)=4(6m)+4(3)=24m+12




A. 24m+12 and 12(2m+1)
B. distributive property
C. if m=1, we get 36=36
3 0
3 years ago
An isosceles triangle with base 12mm and perimeter 28mm
olga55 [171]

Answer:

Side lengths of 12,8,8

Step-by-step explanation:

In an isosceles triangle the base is different from the other 2 sides which are the same so

28=12+2x (x being the side of the repeat sides)

14=6+x (divide both sides by 2)

8=x (subtract 6 from both sides) so

Side lengths of 12,8,8

5 0
3 years ago
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