Answer:
22
Step-by-step explanation:
We are given the expression:—

When n = 5, substitute/change n to 5:—

Evaluate:—

__________________________________________________________
<u>Summary</u>
<u>Substitution</u>
Changing or replacing from a term to another terms/expression is called substitution.
Examples:—
If we are given the expression
and we want to find the value when y = 4, simply replace y-term to 4.

__________________________________________________________
If you have any doubts regarding my answer/explanation, do not hesitate to ask in comment!
Question 1 might be B. 0.3
Question 2 might be D.TW, TM, CW, CM, HW, HM
I'm not 100% sure though
Answer:
Log₆ (A⁵C² / D⁶) = –13
Step-by-step explanation:
From the question given above,
Log₆ A = 1
Log₆ C = 3
Log₆ D = 4
Log₆ (A⁵C² / D⁶) =?
Recall:
Log MN / U = Log M + Log N – Log U
Therefore,
Log₆ (A⁵C² / D⁶) = Log₆ A⁵ + Log₆ C² – Log₆ D⁶
Recall:
Log Mⁿ = nLog M
Thus,
Log₆ A⁵ + Log₆ C² – Log₆ D⁶
= 5Log₆ A + 2Log₆ C – 6Log₆ D
Log₆ A = 1
Log₆ C = 3
Log₆ D = 4
= 5(1) + 2(3) – 6(4)
= 5 + 6 – 24
= 11 – 24
= –13
Therefore,
Log₆ (A⁵C² / D⁶) = –13
Answer:
0.04395604395
Step-by-step explanation:
Answer: 529 students
Step-by-step explanation:
To solve this, we will be using the formula for finding averages:
> (total sum of student weights) ÷ (total sum of students) = (average of student weights)
Plugging in the values that are given in the problem, you get:
> 16,293.2 ÷ x = 30.8
Where x is equal to the total sum of students. From here, it's a simple equation to isolate x, and find out what numerical value x is equal to. In case you are unsure how to do this, I've created a clear step by step process for how to do this (NOTE: The slash represents division, while the asterisk represents multiplication.):
> 16,293.2 / x = 30.8
> (16,293.2 / x) * x = (30.8) * x
> 16,293.2 = 30.8 * x
> (16,293.2) / 30.8 = (30.8 * x) / 30.8
> 529 = x
In total, there are 529 students in the school.