All categories

3 years ago

How to solve this equation t+3=21

1 answer:

5 0

The answer would be
t = 18

Explanation
t + 3= 21
You move the constants to the right
t = 21 - 3
Subtract the numbers
And the answer should be
t = 18

You might be interested in

I need help on 12, I don't know how to make that an expression! Thanks! Please explain!

exis [7]

A rug maker is using a pattern that is a rectangle with a length of 96 inches and a width of 60 inches. The rug maker wants to increase each dimension by a different amount. Let l and w be the increases in the length and width. Write and simplify an expression for the perimeter of the new pattern.

p=2(96+l)+2(60+w)
This is the equation. p is for perimeter. (96+l) represents the original length plus the change in length. The 2 before (96+l) represents that there is one length on each side of the rectangle.
Same for the width. (60+w) represents the original width plus the change in width. The 2 before (60+w) represents that there is one width on each side of the rectangle.
The simplified equation is p=(192+2l)+(120+2w) (this is your answer)

I hope this helps!

3 0

3 years ago

Please help meeeeee for points

padilas [110]

Answer:

Karma ig

Step-by-step explanation:

Idek ;-;

7 0

3 years ago

Read 2 more answers

Find the first three iterates of the function f(z)=z2+c with a value of c=1+2i and an initial value of z0=0

aalyn [17]

Answer:

14x

Step-by-step explanation:

multiply the 2i by the 0 eulogistic quotient

7 0

3 years ago

Read 2 more answers

Using the binomial theorem , obtain the expansion of :

andrezito [222]

Answer:

see explanation

Step-by-step explanation:

Expand both factors and collect like term

Using Pascal' triangle with n = 6 to obtain the coefficients

1 6 15 20 15 6 1

Decreasing powers of 1 from $1^{6}$ to $1^{0}$

Increasing powers of 3x from $(3x)^{0}$ to $(3x)^{6}$

$1+3x)^{6}$

= 1. $1^{6}$ $(3x)^{0}$ + 6. $1^{5}$ $(3x)^{1}$ + 15. $1^{4}$ $(3x)^{2}$ + 20. $1^{3}$ $(3x)^{3}$ + 15.1² $(3x)^{4}$ + 6. $1^{1}$ $(3x)^{5}$ + 1. $1^{0}$ $(3x)^{6}$

= 1 + 18x + 135x² + 540x³ + 1215 $x^{4}$ + 1458 $x^{5}$ + 729 $x^{6}$

--------------------------------------------------------------------------------------

$(1-3x)^{6}$

= 1. $1^{6}$ $(-3x)^{0}$ + 6. $1^{5}$ $(-3x)^{1}$ + 15. $1^{4}$ $(-3x)^{2}$ + 20. $1^{3}$ $(-3x)^{3}$ + 15.1² $(-3x)^{4}$ + 6. $1^{1}$ $(-3x)^{5}$ + 1. $1^{0}$ $(-3x)^{6}$