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andreyandreev [35.5K]
3 years ago
13

Which expression is equivalent to 5y^3/(5y)^-2 A.y^5 B.y^6 C.125y^3 D.125y^5

Mathematics
2 answers:
inn [45]3 years ago
8 0

Answer:

A) Y^5

Step-by-step explanation:

mezya [45]3 years ago
5 0

Answer:

D.125y^5

Step-by-step explanation:

5y^3/(5y)^-2

= 5y^3 * (5y)^2

= 5^(1 + 2) * y^(3+2)

= 5^3 y^5

= 125y^5

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PLEASE HELP ME.<br> THANKS!!!
Veronika [31]

Cos(x) = sin(x + 20o) Use the double cos angle formula

Cos(x) = sin(x)*cos(20) + cos(x)*sin(20) Divide through by cos(x). Tanx = sin(x)/cos(x)

1 = tan(x)*cos(20) + sin(20) Subtract sin(20) from both sides.

1 - sin(20) = tan(x)*cos(20) Calculate the value of 1 - sin(20)

0.65798 = tan(x) * 0.939692 Divide by cos(20)

tan(x) = 0.65795/0.939692

tan(x) = 0.70021 Take the inverse of 0.7) = tan(x)

x = tan-1(0.70021)

x = 35 degrees as expected.

Problem Two

The easiest way to do this is to pick random values and try it. The two acute angles are complementary. So 25 and 65 are random enough.

Let A = 25

Let C = 65

A

Tan(25) = sin(25)/sin(65) ; tan(25) = 0.4663.

sin(25)/sin(65) = 0.4663 Answer

B

Sin(90 - C) = Sin(A)

Tan(90 - A) = Tan(C)

So the question becomes Cos(A) = Tan(C) / sin(A)

Cos(25) = Tan(65)/Sin(25)

0.906 = ? 5.07 This statement isn't true.

C

Sin(65) = Cos(25)/Tan(65)

.906 = 0.4226 C is not the correct answer.

D

D isn't true. The tan does not relate that away. You can find it for yourself.

Cos(A) = Tan(C) You should get 0.906 = 2.14

E

Sin(C) = Cos(A) / Tan(A) I'll leave you to show this is wrong.

Problem 3

The diagram below is for this problem. Cos(x) = 50/100 = 0.5

x = cos-1(0.5)

x = 60 degrees.

Part 2

Sin(60) = opposite / hypotenuse

opposite = sin(60) * hypotenuse

opposite = 86.61 Be sure and round this to whatever the question says to round it to.



4 0
3 years ago
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