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snow_tiger [21]
2 years ago
11

Help me asp 25 points and will mark

Mathematics
1 answer:
denpristay [2]2 years ago
8 0
Y=10x, 10 is the amount of money Miranda earns per hour , x is the amount of hours she works, y is the total amount of money she earns.
For Tommy’s earnings, use slope formula, which is y=y2-y1/x2-x1, take two random points from the table, (4,32) and (5,40)
(4,32) is (x1,y1). (5,40) is (x2,y2)
40-32/5-4= 8/1
The answer is 8. y=8x
Miranda earns more money per hour than Tommy.
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Which fraction, decimal number, and percent are equivalent?
uranmaximum [27]

Answer:

A. 2/5, 0.40, 40%

Step-by-step explanation:

To turn a fractions into a decimal divided the numerator by the denominator. 2/5=0.40.

8 0
2 years ago
Please help due today
umka21 [38]

Answer:

y=2 x=3 i think

Step-by-step explanation:

2y+3=y+5

y=5-3

y=2

4x-3=4y+1

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4x-3=9

4x=9+3

4x=12

x=12/4

×=3

3 0
2 years ago
The director of a marching band asks the band members to line up in rows of four, but one is left over. Then she tries to line t
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I got 81 members. 4 x 20 = 80 81-80=1
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6 0
3 years ago
Can someone please help me with math.
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I think it’s A
6 0
2 years ago
Find the EXACT value of sin(A−B) if cos A = 3/5 where A is in Quadrant IV and cos B = 12/13 where B is in Quadrant IV. Assume al
MissTica

\bf \textit{Sum and Difference Identities} \\\\ sin(\alpha - \beta)=sin(\alpha)cos(\beta)- cos(\alpha)sin(\beta)

well, for both angles A and B we're on the IV Quadrant, meaning, the sine is negative, the cosine is positive, likewise, the opposite side is negative and the adjacent side for the angle is positive.

\bf cos(A)=\cfrac{\stackrel{adjacent}{3}}{\underset{hypotenuse}{5}}\qquad \qquad \stackrel{\textit{getting the opposite side}}{b=\pm\sqrt{5^2-3^2}}\implies b = \pm 4 \\\\\\ \stackrel{IV~Quadrant}{b = -4}\qquad \qquad sin(A)=\cfrac{\stackrel{opposite}{-4}}{\underset{hypotenuse}{5}} \\\\[-0.35em] ~\dotfill\\\\ cos(B)=\cfrac{\stackrel{adjacent}{12}}{\underset{hypotenuse}{13}}\qquad \qquad \stackrel{\textit{getting the opposite side}}{b=\pm\sqrt{13^2-12^2}}\implies b = \pm 5

\bf \stackrel{IV~Quadrant}{b = -5}\qquad \qquad sin(B)=\cfrac{\stackrel{opposite}{-5}}{\underset{hypotenuse}{13}} \\\\[-0.35em] ~\dotfill\\\\ sin(A-B)=\cfrac{-4}{5}\cdot \cfrac{12}{13}-\left( \cfrac{3}{5}\cdot \cfrac{-5}{13} \right)\implies sin(A-B)=\cfrac{-48}{65} - \left( \cfrac{-15}{65} \right) \\\\\\ sin(A-B)=\cfrac{-48}{65} + \cfrac{15}{65}\implies sin(A-B)=\cfrac{-33}{65}

4 0
2 years ago
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