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2 years ago

B(x)=x^3+x^2-9x-9 immmmm loooooost helpppppp

Mathematics

2 answers:

kirill115 [55]2 years ago

5 0

Answer:

Step-by-step explanatio

amid [387]2 years ago

5 0

Answer:

i believe the answer is 12 or 13

Step-by-step explanation:

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How much cardboard needed to construct a rectangular prism measuring 15 inches by 13 inches by 7 inches

aleksandrvk [35]

1,365

hopefully, this helps

4 0

2 years ago

A dolphin jumps from the water at an initial velocity of 16 feet per second. The equation h + -16t^2 + 80t models the dolphin's

Dominik [7]

Answer:

100feet

Step-by-step explanation:

Given the height reached by a dolphin expressed by the equation is h = -16t^2 + 80t. At maximum height, the velocity is zero, hence;

v(t) = dh/dt = -32t + 80

0 = -32t + 80

32t = 80

t = 80/32

t = 2.5secs

Substitute t = 2.5 into the height formula h = -16t^2 + 80t

h = -16(2.5)^2 + 80(2.5)

h = -100+200

h = 100feet

Hence the maximum height the dolphin jumps is 100feet

3 0

2 years ago

PLEASE HELP WILL GIVE BRAINLIEST

lbvjy [14]

Answer:

I don't understand what this is.

Step-by-step explanation:

4 0

2 years ago

Use series to verify that<br><br> <img src="https://tex.z-dn.net/?f=y%3De%5E%7Bx%7D" id="TexFormula1" title="y=e^{x}" alt="y=e^{

SVETLANKA909090 [29]

$y = e^x\\\\\displaystyle y = \sum_{k=1}^{\infty}\frac{x^k}{k!}\\\\\displaystyle y= 1+x+\frac{x^2}{2!} + \frac{x^3}{3!}+\ldots\\\\\displaystyle y' = \frac{d}{dx}\left( 1+x+\frac{x^2}{2!} + \frac{x^3}{3!}+\frac{x^4}{4!}+\ldots\right)\\\\$

$\displaystyle y' = \frac{d}{dx}\left(1\right)+\frac{d}{dx}\left(x\right)+\frac{d}{dx}\left(\frac{x^2}{2!}\right) + \frac{d}{dx}\left(\frac{x^3}{3!}\right) + \frac{d}{dx}\left(\frac{x^4}{4!}\right)+\ldots\\\\\displaystyle y' = 0+1+\frac{2x^1}{2*1} + \frac{3x^2}{3*2!} + \frac{4x^3}{4*3!}+\ldots\\\\\displaystyle y' = 1 + x + \frac{x^2}{2!}+ \frac{x^3}{3!}+\ldots\\\\\displaystyle y' = \sum_{k=1}^{\infty}\frac{x^k}{k!}\\\\\displaystyle y' = e^{x}\\\\$

This shows that $y' = y$ is true when $y = e^x$

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Note 1: A more general solution is $y = Ce^x$ for some constant C.
Note 2: It might be tempting to say the general solution is $y = e^x+C$ , but that is not the case because $y = e^x+C \to y' = e^x+0 = e^x$ and we can see that $y' = y$ would only be true for C = 0, so that is why $y = e^x+C$ does not work.

6 0

2 years ago

Eva bought one share of a company's stock for $42 on Monday. Over the next two days, the

Troyanec [42]

I don’t see a number line, but whatever says that the stock had no increase or decrease is your best bet.

Explanation: we can see it does have a decrease, but the increase the next day overrides it and turns the stock addition to $0

3 0

2 years ago