Which of the following proved that the de broglie’s equation was correct?

Which of the following best describes chemical weathering?

dexar [7]

Answer:

<h3>ir id n becuswe ig gyst makres sensre</h3>

Explanation:

5 0

3 years ago

Read 2 more answers

In a Broadway performance, an 77.0-kg actor swings from a R = 3.65-m-long cable that is horizontal when he starts. At the bottom

krek1111 [17]

Answer: h =1.22 m

Explanation:

from the question we were given the following

mass of performer ( M1 ) = 77 kg

length of cable ( R ) = 3.65 m

mass of costar ( M2 ) = 55 kg

maximum height (h) = ?

acceleration due to gravity (g) = 9.8 m/s^2 (constant value)

We first have to find the velocity of the performer. From the work energy theorem work done = change in kinetic energy

work done = 1/2 x mass x ( (final velocity)^2 - (initial velocity)^2 )

initial velocity is zero in this case because the performer was at rest before swinging, therefore

work done = 1/2 x 77 x ( v^2 - 0)

work done = 38.5 x ( v^2 ) ......equation 1

work done is also equal to m x g x distance ( the distance in this case is the length of the rope), hence equating the two equations we have

m x g x R = 38.5 x ( v^2 )

77 x 9.8 x 3.65 = 38.5 x ( v^2 )

2754.29 = 38.5 x ( v^2 )

( v^2 ) = 71.54

v = 8.4 m/s ( velocity of the performer)

After swinging, the performer picks up his costar and they move together, therefore we can apply the conservation of momentum formula which is

initial momentum of performer (P1) + initial momentum of costar (P2) = final momentum of costar and performer after pick up (Pf)

momentum = mass x velocity therefore the equation above now becomes

(77 x 8.4) + (55 x 0) = (77 +55) x Vf

take note the the initial velocity of the costar is 0 before pick up because he is at rest

651.3 = 132 x Vf

Vf = 4.9 m/s

the performer and his costar is 4.9 m/s after pickup

to finally get their height we can use the energy conservation equation for from after pickup to their maximum height. Take note that their velocity at maximum height is 0

initial Kinetic energy + Initial potential energy = Final potential energy + Final Kinetic energy

where

kinetic energy = 1/2 x m x v^2

potential energy = m x g x h

after pickup they both will have kinetic energy and no potential energy, while at maximum height they will have potential energy and no kinetic energy. Therefore the equation now becomes

initial kinetic energy = final potential energy

(1/2 x (55 + 77) x 4.9^2) + 0 = ( (55 + 77) x 9.8 x h) + 0

1584.7 = 1293 x h

h =1.22 m

3 0

4 years ago

Consider the 4-step staircase. All steps provide an equal elevation gain. The potential energy (PE) on the top step is 16.0 J. D

iragen [17]

Potential energy, PE = 0, 4, 8 and 12 at level 1, 2, 3, 4 respectively.

At Level 5, potential energy = 0 and Kinetic energy = 24 J.

<h3>Potential and Kinetic energy</h3>

Potential energy is the energy a body has by virtue of its position or state.

The formula for calculating the potentials energy of a body is given as:

Potential energy, PE = mgh

where m = mass of the body

g = acceleration due to gravity

h = height

Kinetic energy is the the energy a body has by virtue of its motion.

The formula for calculating kinetic energy of a body is given as:

Kinetic energy, KE = 1/2mv^2

The sum of the kinetic energy and potential energy of a body is constant.

Assume the ball has unit mass; m = 1

g = 10 m/s^2

At the top, total energy of the body = 16 + 8 = 24J

Calculating the gain in height for each step:

At Level 4, PE = 16 J

mgh = 16 J

1 × 10 × h = 16

h = 16/10

h = 1.6 m

Since there are four steps, each step will have a height increase = 1.6/4 = 0.4

At Level 1, h = 0

PE = 0 × 1 × 10

PE = 0 J

At Level 2, h = 0.4 m

PE = 0.4 × 1 × 10

PE = 4 J

At Level 3, h = 0.8 m

PE = 0.8 × 1 × 10

PE = 8 J

At Level 5, PE + KE = 24 J

Since PE = 0

KE = 24

Therefore, potential energy, PE = 0, 4, 8 and 12 at level 1, 2, 3, 4 respectively.

At Level 5, potential energy = 0 and Kinetic energy = 24 J.

Learn more about potential energy and Kinetic energy at: brainly.com/question/14427111

6 0

3 years ago

An electron is placed on a line connecting two fixed point charges of equal charge but the opposite sign. The distance between t

viktelen [127]

Answer:

a) F_net = 6.48 10⁻¹⁸ ( $\frac{1}{x^2} + \frac{1}{(0.300-x)^2}$ ), b) x = 0.15 m

Explanation:

a) In this problem we use that the electric force is a vector, that charges of different signs attract and charges of the same sign repel.

The electric force is given by Coulomb's law

F = $k \frac{q_2q_2}{r^2}$

Since when we have the two negative charges they repel each other and when we fear one negative and the other positive attract each other, the forces point towards the same side, which is why they must be added.

F_net= ∑ F = F₁ + F₂

let's locate a reference system in the load that is on the left side, the distances are

left side - electron r₁ = x

right side -electron r₂ = d-x

let's call the charge of the electron (q) and the fixed charge that has equal magnitude Q

we substitute

F_net = k q Q ( $\frac{1}{r_1^2}+ \frac{1}{r_2^2}$ )

F _net = kqQ ( $\frac{1}{x^2} + \frac{1}{(d-x)^2}$ )

let's substitute the values

F_net = 9 10⁹ 1.6 10⁻¹⁹ 4.50 10⁻⁹ ( $\frac{1}{x^2} + \frac{1}{(0.30-x)^2}$ )

F_net = 6.48 10⁻¹⁸ ( $\frac{1}{x^2} + \frac{1}{(0.300-x)^2}$ )

now we can substitute the value of x from 0.05 m to 0.25 m, the easiest way to do this is in a spreadsheet, in the table the values of the distance (x) and the net force are given

x (m) F (N)

0.05 27.0 10-16

0.10 8.10 10-16

0.15 5.76 10-16

0.20 8.10 10-16

0.25 27.0 10-16

b) in the adjoint we can see a graph of the force against the distance, it can be seen that it has the shape of a parabola with a minimum close to x = 0.15 m

4 0

3 years ago

You are kidnapped by political-science majors (who are upset because you told them political science is not a real science). Alt

Alex787 [66]

A) 2250 meters from starting pont
b) 90 degrees to the right

8 0

4 years ago