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Vaselesa [24]
3 years ago
12

Two identical conducting small spheres are placed with their centers 0.290 m apart. One is given a charge of 12.0 nC and the oth

er a charge of -21.0 nC.Find the electric force exerted by one sphere on the other.
Physics
1 answer:
Solnce55 [7]3 years ago
4 0

Answer:

Force between two identical conducting ball will be 2.65\times 10^{-5}N                        

Explanation:

We have given there is two identical conducting small spheres having charge q_1=12nC=12\times 10^{-9}C and q_2=-21nC=-21\times 10^{-9}C

Distance between centers of the ball is 0.290 m

So r = 0.290 m

We have to fond the electric force between the balls

According to Coulomb's law force between two charges is given by

F=\frac{1}{4\pi \epsilon _0}\frac{q_1_2}{r^2}=\frac{Kq_1q_2}{r^2}

So force F=\frac{9\times 10^{9}\times 12\times 10^{-9}\times 21\times 10^{-9}}{0.293^2}=2.65\times 10^{-5}N

So force between two identical conducting ball will be 2.65\times 10^{-5}N

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