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Vaselesa [24]
3 years ago
12

Two identical conducting small spheres are placed with their centers 0.290 m apart. One is given a charge of 12.0 nC and the oth

er a charge of -21.0 nC.Find the electric force exerted by one sphere on the other.
Physics
1 answer:
Solnce55 [7]3 years ago
4 0

Answer:

Force between two identical conducting ball will be 2.65\times 10^{-5}N                        

Explanation:

We have given there is two identical conducting small spheres having charge q_1=12nC=12\times 10^{-9}C and q_2=-21nC=-21\times 10^{-9}C

Distance between centers of the ball is 0.290 m

So r = 0.290 m

We have to fond the electric force between the balls

According to Coulomb's law force between two charges is given by

F=\frac{1}{4\pi \epsilon _0}\frac{q_1_2}{r^2}=\frac{Kq_1q_2}{r^2}

So force F=\frac{9\times 10^{9}\times 12\times 10^{-9}\times 21\times 10^{-9}}{0.293^2}=2.65\times 10^{-5}N

So force between two identical conducting ball will be 2.65\times 10^{-5}N

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Answer:

x-component of velocity = 5.7 m/s

y-component of velocity = -1.4 m/s          

Explanation:

Use first equation of motion to find components of velocity at a given time:

v = u + at

where, v is  the final velocity, u is the initial velocity, a is the acceleration and t is the time.

Given:

u_x= 0.5 m/s\\u_y=1.2 m/s\\a_x=2 m/s^2\\a_y=-1m/s^2\\t = (2.6-0)s =2.6 s

v_x=u_x+a_xt\\\Rightarrow v_x=0.5+2\times 2.6\\\Rightarrow v_x=5.7 m/s

v_y=u_y+a_yt\\\Rightarrow v_y=1.2-1\times 2.6\\\Rightarrow v_y=-1.4 m/s

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3 years ago
Theweight ofof body is 420N .Calculate its mass​
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42.87

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<u>OR</u>

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420/9.8 which equals 42.87.

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2. What is the percent composition of sulfur in H2SO4?
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Energy of motion is.
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An egg is thrown nearly vertically upward from a point near the cornice of a tall building. It just misses the cornice on the wa
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Answer:

A) 17.7 m/s

B) 15.98 m

C) Zero

E) 9.8 m/s²

Explanation:

given information

distance, h = - 34 m

time, t = 5 s

A) What is the initial speed of the egg?

h - h₀ = v₀t - \frac{1}{2} gt², h₀ = 0

- 34 = v₀ 5 - \frac{1}{2} 9.8 5²

- 34 = 5 v₀ - 122.5

v₀ = 122.5 - 34/5

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B) How high does it rise above its starting point?

v² = v₀² - 2gh

v = 0 (highest point)

2gh = v₀²

h = v₀²/2g

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C) What is the magnitude of its velocity at the highest point?

v = 0 (at highest point)

E) What are the magnitude and direction of its acceleration at the highest point?

g= 9.8 m/s², since the egg is moved vertically, the acceleration is the same as the gravitational acceleration.

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