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lisov135 [29]
3 years ago
13

What is the potential energy of a spring that is compressed 0.65 m by a 25 kg block if the spring constant is 95 N/m?

Physics
2 answers:
Sonbull [250]3 years ago
7 0
E=F*d/2 = M*g*d/2 = 25kg * 9.8 N/kg *0.65m / 2 = 79.625J
USPshnik [31]3 years ago
7 0
The answer is 20 :)                                      
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luda_lava [24]

Answer:

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Explanation:

Radial acceleration, also known as centripetal acceleration, refers to the acceleration of an object along the circular radius. It can be calculated using the formula:

a(r) = v²/r

Where a(r) = radial acceleration

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r = radius of the circular path

According to the information provided in the question, velocity (v) = 17.5m/s, radius = 30m. Hence;

a(r) = v²/r

a(r) = 17.5²/30

a(r) = 10.208333

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Answer:

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Read 2 more answers
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