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vlabodo [156]
4 years ago
11

Using the line of best fit, what is the best approximation for the hourly rate of an individual with 6 years of experience?

Mathematics
2 answers:
Paladinen [302]4 years ago
6 0
Any who has been working in the field for more than 6 years, should be making atleast $12 an  hour easy
KIM [24]4 years ago
4 0
Its 12, if you go to the graph and go to the six at the bottom then go straight up until you hit the blue line then go to the left then you will hit 12 so thats your answer :) I hope this helps.
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What is the slope? I never understood these questions
Rzqust [24]

Answer:

slope=-1/2

Step-by-step explanation:

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3 years ago
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EXPLAIN THE SECOND PART.......
alexdok [17]
\tan^2\theta-\sin^2\theta=\dfrac{\sin^2\theta}{\cos^2\theta}-\sin^2\theta
=\sin^2\theta\left(\dfrac1{\cos^2\theta}-1\right)
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=\sin^2\theta\tan^2\theta

Now if 0^\circ, then both \sin\theta>0 and \tan\theta>0. Adding two positive numbers gives another positive number, so \tan\theta+\sin\theta>0. Why this is useful will be apparent shortly.

Back to the identity:

\tan^2\theta-\sin^2\theta=\tan^2\theta\sin^2\theta

Factorizing the left hand side, we have

(\tan\theta-\sin\theta)(\tan\theta+\sin\theta)=\tan^2\theta\sin^2\theta

Now, any number squared will be positive, which means the right hand side is necessarily greater than 0.

We showed earlier that \tan\theta+\sin\theta>0. So we understand that we have

\underbrace{(\tan\theta-\sin\theta)}_?\underbrace{(\tan\theta+\sin\theta)}_+=\underbrace{\tan^2\theta\sin^2\theta}_+

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3 years ago
PLS ANSWER RN<br><br> What is the area of AJKL?
alex41 [277]

Answer:

8.5

Step-by-step explanation:

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(y2 - y1)/(x2-x1)

(0-1)/(7-3)

m = -1/4

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area = (leg1 x leg2)/2

KL = \sqrt{(7-3)^2 + (0-1)^2} = \sqrt{16 + 1} = \sqrt{17}

KJ = \sqrt{(4-3)^2 + (5-1)^2}= \sqrt{1 + 16} = \sqrt{17}

area = (√17)^2/2 = 17/2 = 8.5

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Andrews [41]
Substitute 4 for x.

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