Question:
Five times the sum of a number and 27 is greater than or equal to six times the sum of that number and 26.
What is the solution set of this problem?
Answer:
Step-by-step explanation:
Given
<em>Represent the number with x</em>
So:
Required
Determine the solution set
Open Both Brackets
Collect Like Terms
Multiply both sides by -1
Hence, the solution set is
Answer:
Parallel :)
Step-by-step explanation:
thats the tea sis.
Let X = total students in musical
Then (1/3) X = number of seniors
1 + 6 + 11 + (1/3)X = X
18 + (1/3)X = X
18 = (2/3)X
(3/2)(18) = X
27 = X
27 students in musical of which one third are seniors,
there are 9 seniors in musical
hope this helped!
1 7/12 becuase 2 neg is a neg, 1 neg and 1 pos is which is bigger in this case it is pos.
It took me a minute, but I understand what it wants you to do.
a^2+b^2=c^2
Find the missing length on that one triangle to the left.
62^2+b^2= 99.2^2
Square the numbers.
3844+b^2= 9840.64
Subtract 3844 on both sides.
b^2= 5996.64
Square root it.
b= 77. 437975 round down to b= 77.4
Now, we can find the length of the other missing side. (x+2)
77.4^2+b^2= 112^2
5990.76+b^2= 12,544
Subtract 5990.76 on both sides.
b^2= 6553.24
Square root it.
b= 80.952085, round to b=81
Now, plug that in.
(x+2)= 81
Subtract 2 on both sides.
x=79 (about)
I hope this helps! Make sure to check my work.
~kaikers
