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3 years ago

the number of hours,h, it takes to wash c numbers of cars at a school fundraiser is inversely proportional to the number of stud

ents,s, needed to wash the cars. Write a equation to represent his relationship

Mathematics

1 answer:

Alex787 [66]3 years ago

3 0

$\bf \qquad \qquad \textit{inverse proportional variation}
\\\\
\textit{\underline{y} varies inversely with \underline{x}}\qquad \qquad y=\cfrac{k}{x}\impliedby 
\begin{array}{llll}
k=constant\ of\\
\qquad variation
\end{array}\\\\
-------------------------------\\\\
\stackrel{\textit{\underline{h}ours to wash a car, is inversely proportional to \underline{s}tudents working on it}}{h=\cfrac{k}{s}}$

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The equation of line perpendicular to given line is:

$y = \frac{2}{3}x-1$

Step-by-step explanation:

Given equation is:

$3x+2y = -8$

First of all, we have to find the slope of the given line

So,

$3x+2y = -8\\2y = -3x-8\\$

Dividing both sides by 2

$\frac{2y}{2} = \frac{-3x-8}{2}\\y = \frac{-3x}{2} - \frac{8}{2}\\y =-\frac{3}{2}x-4$

As the equation is in slope-intercept form, the co-efficient of x will be the slope of the line

$m_1 = -\frac{3}{2}$

As we know that product of slopes of two perpendicular lines is -1

Let m-2 be the slope of line perpendicular to given line

$m_1.m_2 = -1\\-\frac{3}{2} . m_2 = -1\\m_2 = -1 * -\frac{2}{3}\\m_2 = \frac{2}{3}$

Slope-intercept form is:

$y = m_2x+b$

putting the value of the slope

$y = \frac{2}{3}x+b$

Putting the point (3,1) in the equation

$1 = \frac{2}{3}(3) +b\\1 = 2 + b\\b = 1-2\\b = -1$

Putting the value of b

$y = \frac{2}{3}x-1$

Hence,

The equation of line perpendicular to given line is:

$y = \frac{2}{3}x-1$

Keywords: Slope-intercept form, slope

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Answer:

Step-by-step explanation:

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3 years ago

jenna's rectangular garden borders a wall. she buys 80 ft of fencing. what are the dimensions of the garden that will maximize i

FrozenT [24]

Answer:

The dimensions are x =20 and y=20 of the garden that will maximize its area is 400

Step-by-step explanation:

Step 1:-

let 'x' be the length and the 'y' be the width of the rectangle

given Jenna's buys 80ft of fencing of rectangle so the perimeter of the rectangle is 2(x +y) = 80

x + y =40

y = 40 -x

now the area of the rectangle A = length X width

A = x y

substitute 'y' value in above A = x (40 - x)

A = 40 x - x^2 .....(1)

Step :2

now differentiating equation (1) with respective to 'x'

$\frac{dA}{dx} = 40 -2x$ ........(2)

Find the dimensions

$\frac{dA}{dx} = 0$

40 - 2x =0

40 = 2x

x = 20

and y = 40 - x = 40 -20 =20

The dimensions are x =20 and y=20

length = 20 and breadth = 20

Step 3:-

we have to find maximum area

Again differentiating equation (2) with respective to 'x' we get

$\frac{d^2A}{dx^2} = -2$

Now the maximum area A = x y at x =20 and y=20

A = 20 X 20 = 400

Conclusion:-

The dimensions are x =20 and y=20 of the garden that will maximize its area is 400

verification:-

The perimeter = 2(x +y) =80

2(20 +20) =80

2(40) =80

80 =80

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3 years ago