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katrin2010 [14]
3 years ago
5

Write 6.2 as a improper fraction ​

Mathematics
2 answers:
Ad libitum [116K]3 years ago
7 0

Answer: 31/5

Step-by-step explanation:

MAXImum [283]3 years ago
7 0

Answer:31/5

Step-by-step explanation:

6.2/10

31/5

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The appropriate mixing ratio for a solution to kill bloodborne pathogens is 1 part chlorine to 10 parts water. If you are mixing
lorasvet [3.4K]
The ratio is:
Chlorine : Water = 1 : 10
m ( Water ) = 15 ounces
m ( Chlorine ) = x
x : 15 = 1 : 10
10 x = 15 * 1
10 x = 15
x = 15 : 10
x = 1.5 ounces
Answer:
We need to add 1.5 ounces of Chlorine for the correct ratio.
8 0
3 years ago
А<br> 2. Find the values of x and 3x.
jolli1 [7]

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Step-by-step explanation:

For the equation y = x - 3x + 4x + 5, tind the point of inflection. ...  Find the indicated derivative using the definition f(x) = 2x4+3x3-2x+7: f'(0).

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3 years ago
What is the first step to solving this equation (5x-11=42)?
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2 years ago
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An independent-measures research study was used to compare two treatment conditions with n= 12 participants in each treatment. T
Maurinko [17]

Answer:

(a) The data indicate a significant difference between the two treatments.

(b) The data do not indicate a significant difference between the two treatments.

(c) The data indicate a significant difference between the two treatments.

Step-by-step explanation:

Null hypothesis: There is no difference between the two treatments.

Alternate hypothesis: There is a significant difference between the two treatments.

Data given:

M1 = 55

M2 = 52

s1^2 = 8

s2^2 = 4

n1 = 12

n2 = 12

Pooled variance = [(n1-1)s1^2 + (n2-1)s2^2] ÷ (n1+n2-2) = [(12-1)8 + (12-1)4] ÷ (12+12-2) = 132 ÷ 22 = 6

Test statistic (t) = (M1 - M2) ÷ sqrt [pooled variance (1/n1 + 1/n2)] = (55 - 52) ÷ sqrt[6(1/6 + 1/6)] = 3 ÷ 1.414 = 2.122

Degree of freedom = n1+n2-2 = 12+12-2 = 22

(a) For a two-tailed test with a 0.05 (5%) significance level and 23 degrees of freedom, the critical values are -2.069 and 2.069.

Conclusion:

Reject the null hypothesis because the test statistic 2.122 falls outside the region bounded by the critical values.

(b) For a two-tailed test with a 0.01 (1%) significance level and 23 degrees of freedom, the critical values are -2.807 and 2.807.

Conclusion:

Fail to reject the null hypothesis because the test statistic 2.122 falls within the region bounded by the critical values.

(c) For a one-tailed test with 0.05 (5%) significance level and 23 degrees of freedom, the critical value is 1.714.

Conclusion:

Reject the null hypothesis because the test statistic 2.122 is greater than the critical value 1.714.

6 0
3 years ago
Need help on these three. thanks:))
Anton [14]
1. 0.3% or 30%
2. 15 minutes
3. 48 times
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3 years ago
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