Answer:

Step-by-step explanation:
b increased by 16 is at most 20 in equation form
increased means add
b+16
is at most means 

We proved that formula using the trigonometry relations sin3A + sinA = 4sinAcos^2A.
In the given question,
We have to prove the formula sin 3A+sin A = 4sinAcos^2A
The given expression is sin 3A+sin A = 4sinAcos^2A
To prove the formula we take the left side terms to the right side terms
The left side is sin 3A+sin A.
As we know that sin 3A = 3sinA − 4sin^3A
To solve the left side we put the value of sin 3A in sin 3A+sin A.
=sin 3A+sin A
=3sinA − 4sin^3A+sin A
Simplifying
= (3sinA+sin A) − 4sin^3A
= 4sinA − 4sin^3A
Taking 4sinA common from both terms
= 4sinA(1 − sin^2A)
As we know that cos^2A=1 − sin^2A. So
= 4sinAcos^2A
We proved the right hand side.
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Answer:
0.0133
Step-by-step explanation:
Set up the long division.
225 | 3
2 Calculate 300 ÷ 225, which is 1 with a remainder of 75.
0 . 01
_____
225 | 3.
2 . 25
__
75
3 Bring down 0, so that 750 is large enough to be divided by 225.
0 . 01
_____
225 | 3.
2 . 25
__
750
4 Calculate 750 ÷ 225, which is 3 with a remainder of 75.
0 . 013
______
225 | 3.
2.25
__
750
675
___
75
5 Bring down 0, so that 750 is large enough to be divided by 225.
0. 0 1 3
_______
225 | 3.
2.25
__
750
675
_____
75
6 Calculate 750 ÷ 225, which is 3 with a remainder of 75.
0 . 0133
_______
225 | 3.
2. 25
__
750
675
___
750
675
___
75
7 Therefore, 3 ÷ 225 ≈ 0.0133.
Answer: 0.0133
We have that
<span>A).Formulate a recursive sequence modeling the number of grams after n hours.
a(n) = 0.75*a(n-1)
</span>B) .Use the model to calculate the amount of contaminants after the third hour of the experiment.
<span> for the first hour
</span>a(1) = 0.75*a(0)
<span>a0=400 g
a1=(3/4)400 = 300 g
for the second hour
</span>a(2) = 0.75*a(1)
<span>a1=300 g
a2=(3/4)300 = 900/4 g
for the third hour
</span>a(3) = 0.75*a(2)
<span>a2=900/4 g
(3/4)900/4 = 2700/16 = 168.75 g
the answer is </span>168.75 g
Answer:
We are given that there are total 170 toy robots
Number of defective robots out of total 170 toy robots 
We have to find the percentage of toy robots that are disaffected.
The percentage of toy robots that are disaffected is given below:


Therefore, the percent of toy robots that are disaffected is 