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Murljashka [212]
3 years ago
8

Find the value of N please!!

Mathematics
2 answers:
V125BC [204]3 years ago
6 0

Answer:

n = - 5

Step-by-step explanation:

Using the rules of exponents

a^{m} × a^{n} ⇔ a^{(m+n)}

\frac{a^{m} }{a^{n} } ⇔ a^{(m-n)}

Consider the left side

\frac{y^4.y^{n} }{y^2}

= \frac{y^{4+n} }{y^2}

= y^{4+n-2}

= y^{2+n}, then

y^{2+n} = y^{-3}

Since the bases on both sides are the same, equate the exponents

2 + n = - 3 ( subtract 2 from both sides )

n = - 5

babymother [125]3 years ago
6 0
What my mans above said
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A metallurgist has one alloy containing 45% copper and another containing 69% copper. How many pounds of each alloy must be use
lakkis [162]

5.25 pounds of one alloy containing 45% copper and 36.75 pounds of 69% copper is used to make 42 pounds of 66% copper

<h3>What is an equation?</h3>

An equation is an expression that shows the relationship between two or more variables and numbers.

Let x represent the amount of 45% copper and y represent the amount of 66% copper needed to make 42 pounds of a third alloy containing 66% copper. Hence:

x + y = 42   (1)

Also:

0.45x + 0.69y = 42(0.66)   (2)

This gives:

x = 5.25, y = 36.75

5.25 pounds of one alloy containing 45% copper and 36.75 pounds of 69% copper is used to make 42 pounds of 66% copper

Find out more on equation at: brainly.com/question/2972832

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How do i know if this linear? on both
Gre4nikov [31]
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3 years ago
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Can anyone teach plsssss........................ Given that PR= 17cm and SR= 6cm.Find the length, in cm of TS. ​
Lemur [1.5K]

Answer:

9cm

Step-by-step explanation:

  1. Since PQST is a rectangle, ∠QST=∠QSR=∠90º. So triangle QSR is a right triangle.
  2. By the Pythagorean Theorem and that SR=6 and QR=10, we can say that 6^2+b^2=10^2. So, 36+b^2=100. And b^2=64 and b=8. So QS=8.
  3. Now we know that QS=PT=8.
  4. By the Pythagorean Theorem and that PR=17 and PT=8, we can say a^2+8^2=17^2. So, a^2+64=289. And a^2=225 and a=15.
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One of the same-side exterior angles formed by two lines and a transversal is equal to 1/6 of the right angle and is 11 times sm
sergey [27]

One of the same-side exterior angles formed by two lines and a transversal is equal to 1/6 of the right angle and is 11 times smaller than the other angle. Then the lines are parallel

<h3><u>Solution:</u></h3>

Given that, One of the same-side exterior angles formed by two lines and a transversal is equal to 1/6 of the right angle and is 11 times smaller than the other angle.  

We have to prove that the lines are parallel.

If they are parallel, sum of the described angles should be equal to 180 as they are same side exterior angles.

Now, the 1st angle will be 1/6 of right angle is given as:

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Now, sum of angles = 15 + 165 = 180 degrees.

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Hence, the given lines are parallel

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