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Vsevolod [243]
4 years ago
15

Two negative charges that are both -0.3C push each other apart with a force of 19.2 N. How far apart are the two charges?

Physics
1 answer:
Paha777 [63]4 years ago
8 0
<span>Using Coulomb's law: k*(-0.3)*(-0.3)/(d^2)=19.2 D is the distance between the two negative charges</span>
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 A balloon is 3m in diameter and is filled with 5 kg of N2. Find the specific volume of the gas in the balloon. Express it in bo
enyata [817]

Answer:

The the specific volume and weight are 79.16m³/k mol and 49 N.

Explanation:

Given that,

Diameter = 3 m

Mass of N₂ = 5 kg

We need to calculate the volume of balloon

Using formula of volume

V= \dfrac{4}{3}\pi r^3

V= \dfrac{4}{3}\pi \times{\dfrac{d}{2}}^3

V= \dfrac{4}{3}\pi \times(\dfrac{3}{2})^3

V=14.137\ m^3

We need to calculate the specific volume in the balloon

Specific\ volume=\dfrac{Volume}{mass}

Specific\ volume=\dfrac{14.137}{5}

Specific\ volume=2.8274\ m^3/kg

Now, Molar mass of N₂ gas is 0.028 kg/mol

Now, Specific volume of N₂ gas in the balloon is

Specific\ volume =0.028\times2.8274=0.0791672\ m^3/mol

Specific\ volume =79.16m^3/kmol

(b). We need to calculate the weight of the gas in the balloon

Weight of the balloon is dependent on the mass of the gas.

The weight of the gas is given by

W = mg

W = 5\times9.8

W = 49\ N

Hence, The the specific volume and weight are 79.16m³/k mol and 49 N.

7 0
4 years ago
Suppose that an object is moving with constant nonzero acceleration. Which of the following is an accurate statement concerning
Wittaler [7]

Answer: The right answer is b)

Explanation:

By definition, acceleration is the change in velocity (in module or direction) over a given time interval, as follows:

a = (v-v₀) / (t-t₀)

If we take t₀ = 0 (this is completely arbitrary), we can rewrite the equation above, as follows:

v = v₀ + at

We can recognize this function as a linear one, where a represents the slope of the line.

If a is constant, this means that the relationship between the change in velocity and the change in time remains constant, in other words, in equal times, its velocity changes in an equal amount.

Let's suppose that a = 10 m/s/s. (Usually written as 10 m/s²).

This is telling us that each second, the velocity increases 10 m/s.

8 0
3 years ago
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