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AveGali [126]
1 year ago
12

There are pros and cons to both e-readers and paper books. Do you think the pros outweigh the cons more for modern electronic re

aders, or for good old-fashioned paper books? Maybe it simply comes down to personal preferences as opposed to rational decision-making. Which do you prefer? Which do you think is better? Explain.
Physics
1 answer:
lyudmila [28]1 year ago
8 0

E-books have made it easier to carry books across long distances and have made learning  simpler.

<h3>E-books or paper books?</h3>

In the twenty first century, we have seen a sudden budding of technology  such as have never been. Part of this mordern technology is the introduction of electronic books in several formats such as pdf, epub etc.

These books can be read on computers, ipads, laptops, sart phone etc having the appropriate reader software. These ebooks unlike the paper books have eased the inconvienence associated with carrying  paper books which are often bulky from place to place.

Several ebooks could be housed at once in a  smartphone and carried in the pocket. This has made learning easier than ever. Thus, ebooks are better than paper books.

Learn more about ebooks: brainly.com/question/21690258

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We use the formula V=IR where I is current, v is voltage, and R is resistance. This is V=(3)(10) which is 30 Volts, answer choice (c)
5 0
2 years ago
When a pair of balanced forces acts on an object, the net force that results is.
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D.  Equal to zero.

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3 years ago
Imagine two billiard balls on a pool table. Ball A has a mass of 7 kilograms and ball B has a mass of 2 kilograms. The initial v
olga_2 [115]
A) the final velocity = 66/9 m/s.
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3 years ago
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4 0
2 years ago
A 10.0 g bullet moving at 300m/s is fired into a 1.00 kg block at rest. The bullet emerges (the bullet does not get embedded in
chubhunter [2.5K]

Answer:

v' = 1.5 m/s

Explanation:

given,

mass of the bullet, m = 10 g

initial speed of the bullet, v = 300 m/s

final speed of the bullet after collision, v' = 300/2 = 150 m/s

Mass of the block, M = 1 Kg

initial speed of the block, u = 0 m/s

velocity of the block after collision, u' = ?

using conservation of momentum

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 0.01 x 300 + 0 = 0.01 x 150 + 1 x v'

v' = 0.01 x 150

v' = 1.5 m/s

Speed of the block after collision is equal to v' = 1.5 m/s

5 0
2 years ago
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