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3 years ago

In the case of the vacuum tube and movable stopper, what force moves the stopper?

Physics

2 answers:

taurus [48]3 years ago

7 0

<span>The impact of the air molecules on the outside of the stoppper to sooo</span>

sergejj [24]3 years ago

6 0

I'm pretty sure it's the<span> impact of the air molecules on the outside of the stopper. They exert a net inward force, which is not resisted by anything on the other side.</span>

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A single-turn loop of wire has a resistance of 6.00 Ω and a cross-sectional area 300 cm2 and is perpendicular to a uniform magne

galina1969 [7]

Given that,

Resistance of wire

R = 6.00 Ω

Cross sectional area

A = 300cm² = 0.03m²

Initial magnetic field Bi = 0.2T

Final magnetic field Bf = 3.6T

Time taken t = 0.5s

Current?

From ohms law

V=iR

Then, I = V/R

Therefore, we need to find the induced EMF in the coil

ε = -dΦ/dt

Where Φ =BA

Where the Area is constant

ε = -dΦ/dt = -d(BA)/dt

Since A is constant

ε = -A•dB/dt

ε = -A•(∆B)/∆t

ε = -0.03(3.6—0.2)/0.5

ε = -0.204 V

Then, the magnitude of the EMF is 0.204 V

So,

I = V/R

I = 0.204/6

I = 0.034 Amps

I = 34 mA

Option B is correct.

4 0

4 years ago

A narrow strip of land that connects two larger land masses is called

Katena32 [7]

I think that would be a isthmus

3 0

3 years ago

Compute the velocity of light in calcium fluoride which has dielectric constant of 2.056 .

Aleksandr [31]

Answer:

<h3>idl low presure but de 2.518 has a 6 divide 8 equal di. ko alam?</h3>

4 0

3 years ago

In a hydroelectric power plant, water flows from an elevation of 400 ft to a turbine, where electric power is generated. For an

VashaNatasha [74]

Answer:

$V=3.475ft^3/s=3.48ft^3/s$

Explanation:

We have here values from SI and English Units. I will convert the units to English Units.

We hace for the power P,

$P= 100kW \rightarrow 100kW*(\frac{737.56ft.lbf/s}{1kW})$

$P= 73.7*10^{3}ft.lbf/s$

we have other values such $h=400ft$ and $\gamma= 62.42lb/ft^3$ (specific weight of the water), and 0.85 for \eta

We need to figure the flow rate of the water (V) out, that is,

$V=\frac{P}{\gamma h \eta_0}$

Where $\eta_0$ is the turbine efficiency, at which is,

$\eta_0 = \frac{P}{\gamma Vh}$

Replacing,

$V=\frac{73.7*10^{3}}{62.42*400*0.85}$

$V=3.475ft^3/s$

With this value (the target of this question) we can also calculate the mass flow rate of the waters,

through the density and the flow rate,

$m=\rho V\\m= 3.475*1.94 \\m=6.7415 slugs/s$

converting the slugs to lbm, 1slug = 32.174lbm, we have that the mass flow rate of the water is,

$m= 217lbm/s$

6 0

3 years ago

A rope can withstand a maximum tension of 75 N before snapping . What maximum speed can you spin a 6.0 kg rock in a vertical cir

butalik [34]

Answer:

The maximum speed of the stone without breaking the rope is 4.33 m/s.

Explanation:

Given;

maximum tension the rope can withstand, T = 75 N

mass of the rock, m = 6 kg

radius of the circle, r = 1.5 m

As the stone spin in a vertical circle, it performs circular motion with centripetal acceleration directed inwards. The maximum centripetal force during this motion will be equal to maximum tension on the rope.

$F_c,_m_a_x = T = \frac{MV_m_a_x^{2} }{r}\\\\V_m_a_x^{2} = \frac{Tr}{M}\\\\V_m_a_x = \sqrt{\frac{75*1.5}{6}}\\\\V_m_a_x = 4.33 \ m/s$

Therefore, the maximum speed of the stone without breaking the rope is 4.33 m/s.

7 0

4 years ago