Kinetic energy evades the ball jumping higher than the kid
the new momentum would be 40000 units as momentum = mass × velocity
To solve this problem we will apply the concepts related to the electric field, linear charge density and electrostatic force.
The electric field is

Here,
= Linear charge density
= Permittivity of free space
r = Distance
The linear charge density can be written as,
Linear charge density is given as

Replacing,


The initial and final electric Force can be written as function of the charge and the electric field as


If we replace the value for the electric field we have,

Length is one third at the end, then

The ratio of the force is


Therefore the required ratio is 3
The correct answer is the following.
The forces that act on the piano are: 2) gravitational force acting on the piano (piano's weight). 5) force of the floor on the piano (normal force). 7) force of Chadwick on the piano.
As we see in the picture that I have attached is Chadwick pushing the piano in a horizontal plane. So Chadwick is applying a force that produces an acceleration. It is his force on the piano plus the acceleration of the weight of the piano, it's a gravitational force. This is pure physics applied to an object.
Answer:
a rock of 50kg should be placed =drock=0.5m from the pivot point of see saw
Explanation:
τchild=τrock
Use the equation for torque in this equation.
(F)child(d)child)=(F)rock(d)rock)
The force of each object will be equal to the force of gravity.
(m)childg(d)child)=(m)rockg(d)rock)
Gravity can be canceled from each side of the equation. for simplicity.
(m)child(d)child)=(m)rock(d)rock)
Now we can use the mass of the rock and the mass of the child. The total length of the seesaw is two meters, and the child sits at one end. The child's distance from the center of the seesaw will be one meter.
(25kg)(1m)=(50kg)drock
Solve for the distance between the rock and the center of the seesaw.
drock=25kg⋅m50kg
drock=0.5m