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denis-greek [22]
3 years ago
12

Which of the following statements about the

Physics
1 answer:
Komok [63]3 years ago
8 0

Answer: the answer is A

Explanation: just did it

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A child bouncing a ball. Which law of motion does the situation describe?​
vlada-n [284]
Kinetic energy evades the ball jumping higher than the kid
7 0
3 years ago
A 500 kg car possesses 20000 units of momentum . What would be the cars new momentum if it’s velocity was doubled .
PilotLPTM [1.2K]

the new momentum would be 40000 units as momentum = mass × velocity

3 0
3 years ago
A small segment of wire contains 10 nC of charge. The segment is shrunk to one-third of its original length. A proton is very fa
Alik [6]

To solve this problem we will apply the concepts related to the electric field, linear charge density and electrostatic force.

The electric field is

E = \frac{\lambda}{2\pi \epsilon_0 r}

Here,

\lambda= Linear charge density

\epsilon_0 = Permittivity of free space

r = Distance

The linear charge density can be written as,

Linear charge density is given as

\lambda = \frac{q}{L}

Replacing,

E = \frac{\frac{q}{L}}{2\pi \epsilon_0 r}

E = \frac{q}{2\pi \epsilon_0 rL}

The initial and final electric Force can be written as function of the charge and the electric field as

F_i = E_i q

F_f = E_f q

If we replace the value for the electric field we have,

F_i = (\frac{q}{2\pi \epsilon_0 rL})q = (\frac{q^2}{2\pi \epsilon_0 rL})

Length is one third at the end, then

F_f = (\frac{q}{2\pi \epsilon_0 r(L/3)})q = (\frac{3q^2}{2\pi \epsilon_0 rL})

The ratio of the force is

\frac{F_f}{F_i} = \frac{(\frac{3q^2}{2\pi \epsilon_0 rL})}{(\frac{q^2}{2\pi \epsilon_0 rL})}

\frac{F_f}{F_i} = 3

Therefore the required ratio is 3

7 0
3 years ago
Identify the forces acting on the object of interest. From the list below, select the forces that act on the piano.
bekas [8.4K]

The correct answer is the following.

The forces that act on the piano are: 2) gravitational force acting on the piano (piano's weight). 5) force of the floor on the piano (normal force). 7) force of Chadwick on the piano.

As we see in the picture that I have attached is Chadwick pushing the piano in a horizontal plane. So Chadwick is applying a force that produces an acceleration. It is his force on the piano plus the acceleration of the weight of the piano, it's a gravitational force. This is pure physics applied to an object.

5 0
3 years ago
A 25kg child sits on one end of a 2m see saw. How far from the pivot point should a rock of 50kg be placed on the other side of
ivann1987 [24]

Answer:

a rock of 50kg should be placed =drock=0.5m from the pivot point of see saw

Explanation:

τchild=τrock  

Use the equation for torque in this equation.

(F)child(d)child)=(F)rock(d)rock)

The force of each object will be equal to the force of gravity.

(m)childg(d)child)=(m)rockg(d)rock)

Gravity can be canceled from each side of the equation. for simplicity.

 (m)child(d)child)=(m)rock(d)rock)  

Now we can use the mass of the rock and the mass of the child. The total length of the seesaw is two meters, and the child sits at one end. The child's distance from the center of the seesaw will be one meter.

(25kg)(1m)=(50kg)drock

Solve for the distance between the rock and the center of the seesaw.

drock=25kg⋅m50kg

drock=0.5m

6 0
3 years ago
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