The number of waves arriving at the same place in a fixed amount
of time is directly related to the frequency of the waves.
Answer:
Explanation:
a ) V( primary ) = 100 V
V( secondary ) = 10 V
No of turns ( secondary ) / No of turns ( primary ) = 10 / 100
= 1 / 10
b ) current in secondary
= volt ( secondary ) / resistance
= 10 /6 = 1.67 A
c )
Average power to secondary
= V ( secondary ) x current ( secondary )
= 10 x 10 / 6
= 16.67 W
d )
Power in primary = power in secondary = 16.67 W
e ) current drawn by ac line ( primary )
Volt ( primary ) x current ( primary ) = power in primary
= 16.67
current ( primary )
= 16.67 / 100
= 0.167 A
And what about it?????????
Answer
Assuming
east is the positive x direction
north is the positive y direction
initial velocity , u = 19 j m/s
a)
acceleration , a = 1.6 j m/s^2
Using first equation of motion
v = u + a × t
v = 19 + 5.6× 1.6
v = 28 j m/s
the velocity of the car after 5.6 s is 28 m/s north
b)
acceleration , a = -1.5 j m/s^2
Using first equation of motion
v = u + a × t
v = 19 - 5.6 ×1.5
v = 10.6 j m/s
the velocity of the car after 5.6 s is 10.6 m/s north
(a) Determine the circumference of the Earth through the equation,
C = 2πr
Substituting the known values,
C = 2π(1.50 x 10¹¹ m)
C = 9.424 x 10¹¹ m
Then, divide the answer by time which is given to a year which is equal to 31536000 s.
orbital speed = (9.424 x 10¹¹ m)/31536000 s
orbital speed = 29883.307 m/s
Hence, the orbital speed of the Earth is ~29883.307 m/s.
(b) The mass of the sun is ~1.9891 x 10³⁰ kg.
