Answer:
x=3,x=1
y=2,y=-2
Step-by-step explanation:
ANSWER
My answer is in the photo above
Answer:
(5.5,8.5)
Step-by-step explanation:
(8+3)÷2=5.5
(15+2)÷2=8.5
Answer:
d=117.33 m
Step-by-step explanation:
Initial velocity of planes, u = 0 (because they are at rest)
Acceleration, a = 3.3 m/s²
Final take off speed, v = 88 m/s
We need to find the minimum allowed length for the runway. Let it is d. d will be the distance. It can be calculated using third equation of motion as follows :

Putting all the values, we get :

Hence, the minimum allowed length for the runway is 117.33 m.
First make x the subject of the relation:-
f(x) = 2x - 4
2x = f(x) + 4
x = (f(x) + 4) / 2
Now replace x by the inverse f-1(x) and f(x) by x :-
f-1(x) = (x + 4) / 2