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TiliK225 [7]
3 years ago
13

Pls help

Mathematics
2 answers:
sweet [91]3 years ago
7 0

Answer:

B

Step-by-step explanation:

Given

x² + 2x + 8 ( to find the solutions equate to zero )

x² + 2x + 8 = 0 ( subtract 8 from both sides )

x² + 2x = - 8

To solve we can use the method of completing the square

add ( half the coefficient of the x- term )² to both sides

x² + 2(1)x + 1 = - 8 + 1

(x + 1)² = - 7 ( take the square root of both sides )

x + 1 = ± \sqrt{-7} = ± i \sqrt{7}

Subtract 1 from both sides )

x = - 1 ± i \sqrt{7}

astra-53 [7]3 years ago
4 0

Answer:

2+i times the square root of 7

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Answer:

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3 years ago
Read 2 more answers
How many liters of a 10% antifreeze solution and a 40% antifreeze solution must be mixed to make 15 liters of a 25% solution? Ro
butalik [34]

Answer:

7.5 liters of a 10% antifreeze solution AND

7.5 liters of a 40% antifreeze solution

Step-by-step explanation:

According to the question,we were asked to find out how many liters of 10% anti freeze solution and 40% anti freeze each to make a 15 liters 25% mixture

Let’s call

the amount of liters needed of our 10% solution “x”. So, how

many liters do we need of the 40% solution? Well, there are 15

liters in total, x liters have been spoken for, so what remains

of our allotted 10 liters then, is 15-x.

Now let's solve for "x"

10% of x + 40% of (15 - x) = 25% of 15 liters

0.1x + 0.4(15 - x) = 0.25(15)

0.1x + 6 - 0.4x = 3.75

Collect the like terms and we have

0.3x = 2.25

x = 2.25 × 3

X = 7.5(Liters for the 10% anti freeze solution)

The 40% solution= 15 - 7.5 = 7.5 liters

Since "X" was used to fill for the unknown amount of 10% anti freeze solution,we have 7.5 liters of the 10% solution and another 7.5 liters for the 40% solution to end up with 15 liters of the desired 25% solution.

8 0
3 years ago
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