Question

A 2% suspension in saline contains how many ml per 5 ml saline?

Answer 1

Answer:

There are 0.1 mililiters in 5 milimeters saline.

Step-by-step explanation:

A 2 % suspension means that 2 % of the volume of a given substance per each 100 milimeters of saline. That is:

$r = \frac{V_{sub}}{V_{sal}}$

$V_{sub} = r\cdot V_{sal}$

Where:

$r$ - Suspension ratio, dimensionless.

$V_{sal}$ - Saline volume, measured in milimeters.

$V_{sub}$ - Substance volume, measured in milimeters.

Given that $r = 0.02$ and $V_{sal} = 5\,mL$, the volume of the substance is:

$V_{sub} = 0.02\cdot (5\,mL)$

$V_{sub} = 0.1\,mL$

There are 0.1 mililiters in 5 milimeters saline.