The valence electrons determine how reactive an element is, and since Sodium and other alkali metals could easily lose an electron, they become very reactive to be stable.
Answer: Strong (b)
Explanation:
INFRARED ACTIVE BONDS
Not all covalent bonds display bands in the IR spectrum. Only polar bonds do so. These are referred to as IR active.
The intensity of the bands depends on the magnitude of the dipole moment associated with the bond in question:
Strongly polar bonds such as carbonyl groups (C=0) produce strong bands.
The question is incomplete. The complete question is :
C. Balance these fossil-fuel combustion reactions. (1 point)
C8H18(g) + 12.5O2(g) → ____CO2(g) + 9H2O(g) + heat
CH4(g) + ____O2(g) → ____CO2(g) + ____H2O(g) + heat
C3H8(g) + ____O2(g) → ____CO2(g) + ____H2O(g) + heat
C6H6(g) + ____O2(g) → ____CO2(g) + ____H2O(g) + heat
Solution :
C8H18(g) + 12.5O2(g) → __8__CO2(g) + 9H2O(g) + heat
When 1 part of octane reacts with 12.5 parts of oxygen, it gives 8 parts of carbon dioxide and 9 parts of water along with liberation of energy.
CH4(g) + __2__O2(g) → __1__CO2(g) + __2__H2O(g) + heat
When 1 part of methane reacts with 2 parts of oxygen, it gives 1 part of carbon dioxide and 2 parts of water along with liberation of energy.
C3H8(g) + __5__O2(g) → __3__CO2(g) + __4__H2O(g) + heat
When 1 part of propane reacts with 5 parts of oxygen, it gives 3 part of carbon dioxide and 4 parts of water along with liberation of energy.
C6H6(g) + __1/2__O2(g) → __6__CO2(g) + __3__H2O(g) + heat
When 1 part of propane reacts with 1/2 parts of oxygen, it gives 6 part of carbon dioxide and 3 parts of water along with liberation of energy.
Answer:
Explanation:
scientific notation of 750000 is
7.5*10^5
pH of the solution is calculated using the following formula:
![pH=-log{[H^{+}]}](https://tex.z-dn.net/?f=pH%3D-log%7B%5BH%5E%7B%2B%7D%5D%7D)
Here, ![[H^{+}]](https://tex.z-dn.net/?f=%5BH%5E%7B%2B%7D%5D)
is concentration of hydrogen ion.
Initial value of pH is 6.7, calculate concentration of hydrogen ion from this as follows:
![[H^{+}]=10^{-pH}](https://tex.z-dn.net/?f=%5BH%5E%7B%2B%7D%5D%3D10%5E%7B-pH%7D)
Putting the value,
![[H^{+}]=10^{-6.7}=1.9952\times 10^{-7}](https://tex.z-dn.net/?f=%5BH%5E%7B%2B%7D%5D%3D10%5E%7B-6.7%7D%3D1.9952%5Ctimes%2010%5E%7B-7%7D)
Thus, initial concentration of hydrogen ion is 
.
Now, final pH value is 8.7, calculate concentration of hydrogen ion as follows:
![[H^{+}]=10^{-8.7}=1.9952\times 10^{-9}](https://tex.z-dn.net/?f=%5BH%5E%7B%2B%7D%5D%3D10%5E%7B-8.7%7D%3D1.9952%5Ctimes%2010%5E%7B-9%7D)
Thus, final concentration of hydrogen ion is 
.
The ratio of final to initial value will be:
Thus, if pH increases from 6.7 to 8.7, concentration of hydrogen ion becomes 
of the initial value.
