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ipn [44]
2 years ago
14

This investigation is a controlled experiment, so you can change only one variable at a time. Which reactant do you think Koby s

hould change, the baking soda or the vinegar? Give a reason for your choice.
Chemistry
1 answer:
WINSTONCH [101]2 years ago
6 0

Answer:

The baking soda

Explanation:

This is the more reactive part of the experiment. The more baking soda there is (compared to the vinegar), the stronger the reaction.

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A gas of 19 mL at a pressure of 740 mmHg can be expected to change its pressure when its volume changes to 30. mL. Express its n
Soloha48 [4]

To solve this we assume that the gas is an ideal gas. Then, we can use the ideal gas equation which is expressed as PV = nRT. At a constant temperature and number of moles of the gas the product of PV is equal to some constant. At another set of condition of temperature, the constant is still the same. Calculations are as follows:

 

P1V1 =P2V2

P2 = P1V1/V2

P2 = 740mmhg x 19 mL / 30 mL

<span>P2 = 468.67 mmHg = 0.62 atm</span>

6 0
3 years ago
Read 2 more answers
Please help me with these questions, im not understanding :(
azamat

Answer:

this is all the answers i hope you have a good day

Explanation:

may i please have a branlliests

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8 0
3 years ago
If the pressure, volume, and temperature of a gas are known, which can most likely be found by using the ideal gas law?
alukav5142 [94]

Answer:

the moral amount of the gas.

5 0
3 years ago
Determine the mass of MgCl2 needed to create a 100. ml solution with a concentration of 3.00 M.
kiruha [24]

Explanation:

1000ml \: contain \: 3 \: moles \\ 100 \: ml \: will \: contain \: ( \frac{100 \times 3}{1000} ) \: moles \\  = 0.3 \: moles \\ RFM = 95 \\ 1 \: mole \: weighs \: 95 \: g \\ 0.3 \: moles \: weigh \: ( \frac{(0.3 \times 95)}{1}  \: g \\  = 28.5 \: g \: of \: magnesium \: chloride

5 0
2 years ago
How many liters of 18.5 molar HCl stock solution will be needed to make 25.0 liters of 1.5 molar HCl solution? Show the work use
Lera25 [3.4K]
1) Find the number of moles that the final solution must contain

M = n / liters of solution => n = M*liters of solution

n = 1.5 mol/liter * 25.0 liter = 37.5 moles

2) Find how many liters of the stock solution contain 37.5 moles of HCL

M = n / liters of sulution => liters of solution = n / M = 37.5 mol / 18.5 mol/liter

liter of solution = 2.03 liter

Answer: 2.03 liter
7 0
3 years ago
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