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hoa [83]
3 years ago
8

Which of these equations have no solution? Check all that apply.

Mathematics
3 answers:
pogonyaev3 years ago
8 0

Answer: 2(x + 2) + 2 = 2(x + 3) + 1

Steps:

2x + 6 = 2x + 7

<em>Subtract 6 from both sides</em>

2x + 6 - 6 = 2x + 7 - 6

<em>Simplify</em>

2x = 2x + 1

<em>Subtract 2x from both sides</em>

2x - 2x = 2x + 1 - 2x

<em>Simplify</em>

0 = 1

The sides are not equal.

NO SOLUTION

ollegr [7]3 years ago
6 0

Answer:

the first one

Step-by-step explanation:

XxMandy_WolfxX2 years ago
0 0

A B and E!!!! yayay

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Solve each equation 3m-3/5=2m-1/2
Kazeer [188]

Answer:

m= 1/10

Step-by-step explanation:

1. Move the terms so that will be 3m - 2m=-1/2 + 3/5

2. Subtract the m values so that will be 3m - 2m= 1 or m

3. Calculate the sum.

4. So the answer will be m= 1/10. M because we subtracted 2 from 3 which make us 1 so we say it m and 1/10 by doing 1/2 + 3/5.

3 0
3 years ago
Read 2 more answers
Given circle Q with a measure of SR=120° and a radius of 9 feet, as shown below.
Pie

Answer:

18.85 feet

Step-by-step explanation:

Determine the arc length of SR

Arc length = θ/360 × 2πr

r = 9 feet

θ =120°

Arc length = 120/360 × 2 × π × 9

= 18.849555922 feet

Approximately = 18.85 feet

Therefore, the arc length of SR = 18.85 feet

6 0
3 years ago
I am a 3 digit number. The sum of my digits is 14. My ones place is 3 times as much as my hundreds place.
Murrr4er [49]

Answer:

329

Step-by-step explanation:

4 0
2 years ago
The ball used in a soccer game may not weigh more than 16 ounces or less
Liono4ka [1.6K]
In order for the ball to be used in the game, it must be able to meet the minimum and maximum weight requirements. These are the limits of the weight of the ball. If it exceeds the maximum limit of 16 ounces or below the minimum limit of 14 ounces, the ball will not be approved.

So, by adding 1.5 ounces, that would mean that the initial weight of the ball did not reach the minimum limit. The initial weight of the ball, denoted as x, have two possible values. The first value is the initial weight plus added with 1.5 ounces would reach 14 ounces.

x + 1.5 = 14
x = 12.5 ounces

The other scenario is when the initial weight is added to reach the maximum requirement of 16 ounces

x + 1.5 = 16
x = 14.5 ounces

From both answer, we could conclude that the initial weight has to be 12.5 ounces. If the initial weight were 14.5 ounces to begin with, there should be no need for air. It cans till be approved to be used.
3 0
3 years ago
[79 points if correct]<br>Help me with any 4 questions!<br>Please !!!!​
Anarel [89]

<u>Answer:</u>

<u>(BEFORE YOU SUBMIT IT, PLEASE READ THE WARNING)</u>

QUESTION EIGHT: 2690

QUESTION NINE: 120

QUESTION ELEVEN: 12.5

QUESTION FOURTEEN: 24

<u>Step-by-step explanation:</u>

<u>WARNING!! FOR QUESTIONS WITH INTEREST: I do not know if interest is good or bad (if you get money, or if you lose money. I counted interest as making money, but if you are sure it's not, contact me in the comments and I will solve it again! :)</u>

8.

may 3rd -> july 15th = 73 days

500*0.06 = 30

30 = how much he makes in one day (so he has 530 after 1 day)

30*73 = 2190

500 + 2190 = 2690

9.

210/7 = 30

1% for 3 years = 30

1% for 1 year = 10

100% for 1 year = 1000

2000*0.06 = 120

11.

54,000*0.08 = 4320

54,000/4320 = 12.5

14.

5000*6.26% = 312.5

7500/312.5 = 24

5 0
3 years ago
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