Question

3. A-line segment has endpoints A(–2, 3) and B(6, –1):

Answer 1

The equation of the segments perpendicular bisector is; y = -¹/₂x + 2

How to find the equation of the perpendicular bisector?

i) Since it is a perpendicular bisector, hence point M is the midpoint. Thus;

Midpoint (AB) = [(x₁ + x₂)/2], [(y₁ + y₂)/2] = (x_m, y_m)

Slope AB will be;

m₁ = ((x₁ - x₂)/(y₁ - y₂))

Slope of perpendicular bisector is;

m₂ = -1/m₁

Equation of perpendicular bisector is;

(y - y_m) = m₂(x - x_m)

ii) Midpoint (AB) = [(-2 + 6)/2], [(3 - 1)/2] = (2, 1)

Slope AB will be;

m₁ = ((6 + 2)/(-1 - 3)) = -2

m₂ = -1/-2 = 1/2

Equation of perpendicular bisector is;

(y - 1) = -¹/₂(x - 2)

y - 1 = -¹/₂x + 1

y = -¹/₂x + 2

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