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k0ka [10]
3 years ago
6

Determine the answer to the equation 30 km/h × 17 h =

Physics
1 answer:
Jobisdone [24]3 years ago
5 0
30 km/h * 17 h =  30*17  km/h  *h
                         =    510 km
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What are the two <br>factors in which weight of object depends?​
insens350 [35]

Answer:

An object's weight depends on its mass (the amount of matter it consists of) and the strength of the gravitational pull.

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3 years ago
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A 60.watt light bulb runs for 5.0 seconds. How much energy does it use?
VikaD [51]

"watt" means "Joule of energy per second"

"60 watts" means "60 Joules per second"

(60 joules per second) x (5 seconds) = <em>300 Joules of energy</em>

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4 years ago
A Carnot engine absorbs 1, 3 MJ of heat at 427 degree C and exhausts heat to a reservoir at 90 degree C. How much work does it d
Alex17521 [72]
<span>Carnot cycle efficiency = work done/heat supplied = (Th - Tc)/Th where, Th is temperature of hot reservoir and Tc is temperature of cold reservoir. we have given the values as Heat supplied = 1.3 MJ or 1300 KJ, Th = 427 degree C and Tc = 90 degree C. converting degree Celsius to kelvin temperatures, Th = 427 + 273 = 700 K Tc = 90 +273 = 363 solving equations, (700 - 363)/700 = work done / 1300 work done = 625.86 KJ i.e. 0.626 MJ work is done .</span>
5 0
3 years ago
Your friend has informed you that his/her uncle has decided not to look after him anymore.Write to your friends uncle giving him
Lorico [155]

Answer:

Cause you are their family and they need you. Do you wanna be someone who abandoned them or be the one they look to and dont dislike into adulthood. Also you signed onto this job no one said it was going to be easy but you making your life easier but harder for someone who is just a kid who still needs you.

7 0
3 years ago
An oxygen molecule consists of two oxygen nuclei, each of massm= 2.7×10−26kg,separated by a distance 1.2×10−10m, and surrounded
fenix001 [56]

Answer:

a)  I = 1,944 10⁻⁴⁶ Kg m²

, b)   I = 7,915 10⁻⁵¹ Kg m²

Explanation:

a) The moment of inertia of point masses is

                 I = m r²

   

The nuclei have a very small size (10-15 m) so we can consider them punctual.

The distance to the center of mass passing through the middle of the two nuclei of equal mass

       r = 0.6 10⁻¹⁰ m

The moment of total inertia

       I = I₁ + I₂ = 2 I₀

       I = 2 2.7 10⁻²⁶ (0.6 10⁻¹⁰)²

       I = 1,944 10⁻⁴⁶ Kg m²

The kinetic energy of the rotation is

      w = h / 2π

      K = ½ I w²

      K = ½ 1,944 10⁻⁴⁶ (h / 2π)² = ½ 1.944 10⁻⁴⁶ (6.63 10⁻³⁴ / 2π)²

      K = 2.16 10⁻¹¹⁴ J (1eV / 1.6 10⁻¹⁹ J)

      K = 2.16 10⁻⁹⁵ eV

B) the moment of inertia of the electron in the orbit, we can calculate it with the parallel axis theorem

       I =I_{cm} + m R²

       I = m_{e} r² +  m_{e} R²

Where R we calculate it by Pythagoras

      R² = (0.6 10⁻¹⁰)² + (0.5 10⁻¹⁰) 2

      R = √ (0.61 10⁻²⁰)

      R = 0.78 10⁻¹⁰ m

      I = 9.1 10⁻³¹ (0.5 10⁻¹⁰)² + 9.1 10⁻³¹ (0.78 10⁻¹⁰)²

      I = (2,275 +5.54) 10⁻⁵¹

      I = 7,915 10⁻⁵¹ Kg m²

The rotation energy of the electron

      K = ½ I w²

If the angular velocity is the electrons outside the core, its kinetic energy is much lower by an order 10⁵, but the angular velocity of the electrons is much higher.

7 0
3 years ago
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