A satellite orbits the moon for 3685 s. It has an orbital radius of 2008177 m. then the acceleration of the satellite would be 5.832 m/s²
<h3 /><h3>What is a uniform circular motion?</h3>
It is defined as motion when the object is moving in a circle with a constant speed and its velocity is changing with every moment because of the change of direction but the speed of the object is constant in a uniform circular motion
The acceleration during the uniform circular motion is given by the formula
a = v²/r
where a is the acceleration
v is the velocity of the object
r is the radius of the orbit
As given in the problem a satellite orbits the moon for 3685 s. It has an orbital radius of 2008177 m.
velocity of the satellite
v = 2πr/t
v= (2×3.14×2008177)/3685
v = 3422.34 m/s
acceleration of the satellite
a = v²/r
a = 3422.34²/2008177
a = 5.832 m/s²
Thus, the acceleration of the satellite would be 5.832 m/s²
Learn more about uniform circular motion from here
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True? I think jdjsjexosjkxnd
Yeah i think with a car or a plane:)
Answer:
9656.06 meters because youd go 6 miles and 9656.06 is 6 miles but just in meters. I hope this helps :)
Explanation:
Answer:
Explanation:
Applying conservation of momentum
mA v0 + 0 = mA x 12v0 + mB x 92v0
11 mA = - 92mB .
mA / mB = 92 / 11
mA : mB = 92 : 11.
