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Aleksandr [31]
3 years ago
5

Three equal point charges, each with charge 2.00 μC , are placed at the vertices of an equilateral triangle whose sides are of l

ength 0.250 m . What is the electric potential energy U of the system? (Take as zero the potential energy of the three charges when they are infinitely far apart.) U = nothing J
Physics
1 answer:
oksano4ka [1.4K]3 years ago
4 0

Answer:

Explanation:

Energy of system of charges

= k q₁q₂ / r₁₂ + k q₁q₃ / r₁₃ + k q₃q₂ / r₃₂

q₁ , q₂ and q₃ are charges and  r₁₂ , r₁₃ , r₃₂ are densities between them

9 x 10⁹ ( 2x2 x10⁻¹²/ .25 + 2x2 x10⁻¹²/ .25 + 2x2 x10⁻¹²/ .25 )

= 9 x 10⁹  x 3 x 16 x 10⁻¹²

= 432 x 10⁻³

= .432 J .

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Answer:

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Explanation:

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Sum of forces in the parallel direction:

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Draw a free body diagram of the hanging mass m.  There are two forces:

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T = mg, and m = 5 kg, so T = (5 kg) (9.8 m/s²) = 49 N.  Therefore:

v = √(49 N / 0.025 kg/m)

v = 44.3 m/s

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