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Aleksandr [31]
3 years ago
5

Three equal point charges, each with charge 2.00 μC , are placed at the vertices of an equilateral triangle whose sides are of l

ength 0.250 m . What is the electric potential energy U of the system? (Take as zero the potential energy of the three charges when they are infinitely far apart.) U = nothing J
Physics
1 answer:
oksano4ka [1.4K]3 years ago
4 0

Answer:

Explanation:

Energy of system of charges

= k q₁q₂ / r₁₂ + k q₁q₃ / r₁₃ + k q₃q₂ / r₃₂

q₁ , q₂ and q₃ are charges and  r₁₂ , r₁₃ , r₃₂ are densities between them

9 x 10⁹ ( 2x2 x10⁻¹²/ .25 + 2x2 x10⁻¹²/ .25 + 2x2 x10⁻¹²/ .25 )

= 9 x 10⁹  x 3 x 16 x 10⁻¹²

= 432 x 10⁻³

= .432 J .

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0.04455 Hz

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Angle with respect to the east: 56.31^o

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Now, to find the value of the angle \theta, we need to use trigonometry, and in particular the tangent function gives us the ratio between the side of the triangle "opposite" to the angle, divided the side "adjacent" to the angle:

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