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butalik [34]
3 years ago
10

Which is the correct mole ratio of k3po4 to kno3 in the chemical reaction mg(no3)2 + k3po4 ®mg3(po4)2 + kno3?

Chemistry
2 answers:
My name is Ann [436]3 years ago
3 0
<span>3Mg(NO3)2 + 2K3PO4 ---> Mg3(PO4)2 + 6KNO3

n(</span>K3PO4):n(KNO3)=2:6=1:3
n(K3PO4):n(KNO3)=1:3
gizmo_the_mogwai [7]3 years ago
3 0

Answer:

1 : 3

Explanation:

First we right out the balanced chemical equation

3Mg(NO_{3} )_{2} +2K_{3}PO_{4} --->  Mg_{3} (PO_{4} )_{2}+6KNO_{3}

Then from there we use the stoichiometric coefficients to write the molar ratios:

n(K_{3} PO_{4} ): n(KNO_{3} ) = 2:6=1:3

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A 0.479 g sample of nitrogen, oxygen or neon gas occupies a volume of 265 ml at 157 kpa and 20◦c. what is the molar mass and ide
Anna11 [10]
PV = nRT
P = 157 kPa = 157 × 10³ Pa
V = 265 ml = 0.265 l
T = 20°C = 293 K
m = 0.479 g
PV•M = mRT
M = (mRT)/(PV)
M = 0.479 g × 8.314 kPa.l/(mol.K) × 293 K / (157 kPa × 0.265 l)
M ≈ 28.04579 g/mol.
Hence, the Molar Mass of Dinitrogen or Nitrogen Gas is 28 g.
7 0
3 years ago
The K sp for barium fluoride, BaF2, is 2.45 × 10-5. What is the molar solubility of barium fluoride?
lilavasa [31]

Answer: The molar solubility of barium fluoride is 0.0183 moles/liter.

Explanation:

The equation for the reaction will be as follows:

BaF_2\rightarrow Ba^{2+}+2F^

By Stoichiometry,

1 mole of BaF_2 gives 2 moles of F^- and 1 mole of Ba^{2+}

Thus if solubility of BaF_2 is s moles/liter, solubility of Ba^{2+} is s moles/liter and solubility of F^- is 2s moles/liter

Therefore,  

K_sp=[Ba^{2+}][F^{-}]^2

2.45\times 10^{-5}=[s][2s]^2

4s^3=2.45\times 10^{-5}

s^3=6.12\times 10^{-6}moles/liter

s=0.0183moles/liter

Thus the molar solubility of barium fluoride is 0.0183 moles/liter.

8 0
3 years ago
6. A fellow chemist in your research group made 2.4 moles of gas held at a
Whitepunk [10]
Ignore this its not the anwser 2.7g
7 0
3 years ago
The flavoring is what seems to appeal to ______users and it’s what makes vaping seem _________
jek_recluse [69]
The flavoring is what seems to appeal to underage users and it’s what makes vaping seem harmless
4 0
2 years ago
A balloon is filled with 0.250 mole of air at 35°C. If the volume of the balloon is 6.23 liters, what is the absolute pressure o
ruslelena [56]

Answer:

102.807 kPa

Explanation:

There are some assumptions to be made in the answer. The air inside the balloon acts as an ideal gas at a given temperature conditions.

Using the combined ideal gas equation.

PV = nRT\\

P= absolute pressure of air inside the balloon.

V= volume of air inside the balloon (6.23 L= 6.23 * 10⁻³ m³)

n= moles of gas(air). (0.250 mol)

R= Universal gas constant ( 8.314 J / mol·K)

T= Temperature in Kelvin

T= 35 + 273.15 = 308.15 K

So, P = \frac{nRT}{V}

P = \frac{0.250 * 8.314 * 308.15}{6.23 * 10^{-3} }

P= 102.807 * 10³ Pa

P= 102.807 kPa

3 0
3 years ago
Read 2 more answers
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