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3 years ago

How do i solve 6x+2=-2x+22

Mathematics

1 answer:

belka [17]3 years ago

8 0

6x+2=-2x+22

Move -2x to the other side

Sign changes from -2x to +2x

6x+2x+2=-2x+2x+22

6x+2x+2= 22

8x+2= 22

Move +2 to the other side

8x+2-2= 22-2

8x= 22-2

8x= 20

Divide both sides by 8

8x/8= 20/8

x= 20/8

Reduce fraction by dividing by 4

20/4= 5

8/4= 2

Answer:

x= 5/2

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Answer:

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3 years ago

What is the probability that it is not blue?

Alisiya [41]

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3 years ago

A sequence of 1 million iid symbols(+1 and +2), Xi, are transmitted through a channel and summed to produce a new random variabl

Zigmanuir [339]

Answer:

E(w) = 1600000

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Step-by-step explanation:

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solution

sequence will be here as

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0.6 for k = +2

and define is

x1 + x2 + ................ + X1000000

so for expected value for W

E(w) = E( x1 + x2 + ................ + X1000000 ) ......................1

as per the linear probability of expectation

E(w) = 1000000 ( 0.4 × 1 + 0.6 × 2)

E(w) = 1600000

and

for variance of W

v(w) = V ( x1 + x2 + ................ + X1000000 ) ..........................2

v(w) = V x1 + V x2 + ................ + V X1000000

here also same as that xi are i.e d so cov(xi, xj ) = 0 and i ≠ j

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8 0

3 years ago

Evaluate the following expressions if a = 2, b = 3, x = 4, and y = 5.<br> b^2+3(2x-y)

butalik [34]

Hi there! Hopefully this helps!

-------------------------------------------------------------------------------------------------------

<h2 /><h2>Answer: 18</h2><h2>~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~</h2><h2 />

First we need to substitute the value of the variable into the expression.

$b^{2}+3(2x-y)$ = $3^{2} + 3 (2(4)-5)$ .

Now we need to solve $3^{2} + 3 (2(4)-5)$ .

~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

$3^{2} + 3 (2(4)-5)$

First, calculate 3 to the power of 2 and get 9.

$9+3(2\times 4-5)=18$

Multiply 2 and 4 to get 8.

$9+3(8-5) =18$

Subtract 5 from 8 to get 3.

$9+3\times 3 =18$

Multiply 3 and 3 to get 9.

$9+9 =18$ .

<h2>And the answer is, you guessed it, 18!</h2>

7 0

3 years ago