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3 years ago

13

The girls swim team is hosting a fund raiser. They would like to raise at least $500. They are selling candles for $5 and flower

arrangements for $6. The girls estimate that at most they will sell 200 items.

1 answer:

Tanya [424]3 years ago

4 0

Answer:

1. Only candles - 100

$500 / 5 = 100 candles & 0 Flowers

2. Only Flowers - 84

$500 / 6 = 83.3 84 candles & 0 candles

3. Half of each - 50 candles & 47 flowers

$500 / 5 / 2 = 50 candles

$500 / 6 / 2 = 41.6 47 Flowers

Step-by-step explanation:

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How many solutions does this system have?

Umnica [9.8K]

Answer:

one unique solution x=1 y=4

5 0

3 years ago

Write each complex number in rectangular form. a. 2(cos(135)+i sin(135)) b. 3(cos(120))+i sin(120)) c. 5(cos(5pi/4)+i sin(5pi/4)

bagirrra123 [75]

$\bf r\left[ cos\left( \theta \right)+i\ sin\left( \theta \right) \right]\quad 
\begin{cases}
x=rcos(\theta )\\
y=rsin(\theta )
\end{cases}\implies 
\begin{array}{llll}
x&,&y\\
a&&b
\end{array}\implies a+bi\\\\
-------------------------------\\\\
2\left[ cos\left( 135^o\right)+i\ sin\left( 135^o\right) \right]\impliedby r=2\qquad \theta =135^o
\\\\\\
2\left( -\frac{\sqrt{2}}{2} \right)+i\ 2\left( \frac{\sqrt{2}}{2}\right)\implies -\sqrt{2}+\sqrt{2}\ i$

$\bf -------------------------------\\\\
3\left[ cos\left( 120^o\right)+i\ sin\left( 120^o\right) \right]\impliedby r=3\qquad \theta =120^o
\\\\\\
3\left( -\frac{1}{2} \right)+i\ 3\left( \frac{\sqrt{3}}{2}\right)\implies -\frac{3}{2}+\frac{3\sqrt{3}}{2}\ i$

$\bf \\\\
-------------------------------\\\\
5\left[ cos\left( \frac{5\pi }{4}\right)+i\ sin\left( \frac{5\pi }{4}\right) \right]\impliedby r=5\qquad \theta =\frac{5\pi }{4}
\\\\\\
5\left( -\frac{\sqrt{2}}{2} \right)+i\ 5\left( -\frac{\sqrt{2}}{2}\right)\implies -\frac{\sqrt{2}}{2}-\frac{\sqrt{2}}{2}\ i$

$\bf -------------------------------\\\\
4\left[ cos\left( \frac{5\pi }{3}\right)+i\ sin\left( \frac{5\pi }{3}\right) \right]\impliedby r=4\qquad \theta =\frac{5\pi }{3}
\\\\\\
4\left( \frac{1}{2} \right)+i\ 4\left( -\frac{\sqrt{3}}{2}\right)\implies \frac{1}{2}-\frac{\sqrt{3}}{2}\ i$

3 0

3 years ago

Simplify the expression 3x(x – 12x) + 3x2 – 2(x – 2)2. Which statements are true about the process and simplified product? Check

Kisachek [45]

<h3>1. The term $-2(x-2)^2$ is simplified by first squaring the expression (x – 2). </h3><h3>TRUE </h3><h3>2. The simplified product is a binomial. TRUE</h3><h3>3. After multiplying, the like terms are combined by adding and subtracting.</h3><h3>TRUE </h3><h3>4. The parentheses are eliminated through multiplication. TRUE</h3><h3>5. The final simplified product is $-28x^2 + 8x - 8$ FALSE</h3>

Step-by-step explanation:

Here, the given expression is :

$F(x) = 3x(x- 12x) + 3x^2-2(x-2)^2$

Now, let us first solve the given expression step wise:

$F(x) = 3x(x-12x) +3x^2 -2(x-2)^2\\= 3x(-11x) +3x^2 -2(x^2 +4 -4x)\\= -33x^2 + 3x^2 -2x^2 -8+8x\\= -32x^2 +8x - 8\\\implies F(x) = -32x^2 +8x - 8$

Now, here the given statements are:

1. The term $-2(x-2)^2$ is simplified by first squaring the expression (x – 2).

TRUE

2. The simplified product is a binomial. TRUE

3. After multiplying, the like terms are combined by adding and subtracting.

TRUE

4. The parentheses are eliminated through multiplication. TRUE

5. The final simplified product is $-28x^2 + 8x - 8$ FALSE

As the simplified expression is: $(-32x^2 +8x -8)$

7 0

3 years ago

Need help with my homework

Volgvan

Answer:

$\displaystyle y=\frac{16-9x^3}{2x^3 - 3}$

$\displaystyle y=-\frac{56}{13}$

Step-by-step explanation:

<u>Equation Solving</u>

We are given the equation:

$\displaystyle x=\sqrt[3]{\frac{3y+16}{2y+9}}$

i)

To make y as a subject, we need to isolate y, that is, leaving it alone in the left side of the equation, and an expression with no y's to the right side.

We have to make it in steps like follows.

Cube both sides:

$\displaystyle x^3=\left(\sqrt[3]{\frac{3y+16}{2y+9}}\right)^3$

Simplify the radical with the cube:

$\displaystyle x^3=\frac{3y+16}{2y+9}$

Multiply by 2y+9

$\displaystyle x^3(2y+9)=\frac{3y+16}{2y+9}(2y+9)$

Simplify:

$\displaystyle x^3(2y+9)=3y+16$

Operate the parentheses:

$\displaystyle x^3(2y)+x^3(9)=3y+16$

$\displaystyle 2x^3y+9x^3=3y+16$

Subtract 3y and $9x^3$ :

$\displaystyle 2x^3y - 3y=16-9x^3$

Factor y out of the left side:

$\displaystyle y(2x^3 - 3)=16-9x^3$

Divide by $2x^3 - 3$ :

$\mathbf{\displaystyle y=\frac{16-9x^3}{2x^3 - 3}}$

ii) To find y when x=2, substitute:

$\displaystyle y=\frac{16-9\cdot 2^3}{2\cdot 2^3 - 3}$

$\displaystyle y=\frac{16-9\cdot 8}{2\cdot 8 - 3}$

$\displaystyle y=\frac{16-72}{16- 3}$

$\displaystyle y=\frac{-56}{13}$

$\mathbf{\displaystyle y=-\frac{56}{13}}$

8 0

3 years ago

The price of Stock A at 9 A.M. was $15.75. Since then, the price has been increasing at the rate of $0.05 per hour. At noon,

tatyana61 [14]

Answer: I think is 3.5

Step-by-step explanation:

7 0

2 years ago