Answer:
1) A = 0.25 m², 2) V = 0.5 m³, 3) m = 1500 kg, 4) W = 14700 N,
5) P = 58800 Pa
Explanation:
1) The area of the base is square
A = L²
A = 0.5²
A = 0.25 m²
2) The block is a parallelepiped
V = A h
V = 0.25 2
V = 0.5 m³
3) Density is defined
rho = m / V
m = rho V
m = 3000 0.5
m = 1500 kg
4) The weight of a body is
W = mg
W = 1500 9.8
W = 14700 N
5) The pressure is
P = F / A
in this case the force is equal to the weight of the body
P = 14700 / 0.25
P = 58800 Pa
Answer:
2500 J
Explanation:
We can solve the problem by using the first law of thermodynamics:
where
Uf is the final internal energy of the system
Ui is the initial internal energy
Q is the heat added to the system
W is the work done by the system
In this problem, we have:
Q = +1000 J (heat that enters the system)
W = +500 J (work done by the system)
Ui = 2000 J (initial internal energy)
Using these numbers, we can re-arrange the equation to calculate the final internal energy:
Answer:
972 J
Explanation:
At the bottom, all the gravitational potential energy was converted into kinetic energy. If you calculate the GPE, its value will be the same that the KE at the bottom. The GPE can be calculated this way:
GPE = mass×gravity×heigth
GPE = 2.2×9.8×45.08 ≈ 972
Answer:
Explanation:
still water speed is 50 m / 25.0 s = 2.00 m/s or 200 cm/s
In lane 1 the effective speed would be 201.2 cm/s
5000 cm / 201.2 cm/s = 24.85 s
The change is 25.00 - 24.85 = 0.15 s decrease in time
In lane 8, the effective speed would be 198.8 cm/s
5000 cm / 198.8 cm/s = 25.15 s
The change is 25.00 - 25.15 = 0.15 s increase in time
