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forsale [732]
3 years ago
15

Kevin can text 44 words in 8 minutes. At this rate, how many minutes would it take

Physics
1 answer:
lana66690 [7]3 years ago
3 0

Answer:

6 minutes

Explanation:

44 words in 8 minute

i.e, 1 word in 8/44 minutes

i.e, 33. words in (8/44)×33 =6 minutes

✌️:)

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Which of the following elements has the lowest electronegativity?
wlad13 [49]

Answer:I believe it is D I might be wrong

Explanation:

4 0
3 years ago
A bicyclist starts at rest and speeds up to 30 m/s while accelerating at 4 m/s^2. Determine the distance traveled.
raketka [301]

Answer:

Distance, d = 112.5 meters

Explanation:

Initially, the bicyclist is at rest, u = 0

Final speed of the bicyclist, v = 30 m/s

Acceleration of the bicycle, a=4\ m/s^2

Let s is the distance travelled by the bicyclist. The third equation of motion is given as :

v^2-u^2=2as

s=\dfrac{v^2-u^2}{2a}

s=\dfrac{(30)^2}{2\times 4}

s = 112.5 meters

So, the distance travelled by the bicyclist is 112.5 meters. Hence, this is the required solution.

6 0
2 years ago
Which of the following is not an example of centripetal acceleration?
Amanda [17]
An apple falling to the ground is not an example of centripetal acceleration.
5 0
3 years ago
What is the nucleation mechanisms in which nuclei of the solid phase form in the interior of the liquid as atoms cluster togethe
pshichka [43]
I  think its q because i suck on toes 


8 0
3 years ago
What is the length a rubberband was stretched if it has a spring constant of 5700N/m and is currently holding 8600J OF POTENTIAL
lozanna [386]

Answer:

\displaystyle \Delta x=1.74\ m

Explanation:

<u>Elastic Potential Energy </u>

Is the energy stored in an elastic material like a spring of constant k, in which case the energy is proportional to the square of the change of length Δx and the constant k.

\displaystyle PE = \frac{1}{2}k(\Delta x)^2

Given a rubber band of a spring constant of k=5700 N/m that is holding potential energy of PE=8600 J, it's required to find the change of length under these conditions.

Solving for Δx:

\displaystyle \Delta x=\swrt{\frac{2PE}{k}}

Substituting:

\displaystyle \Delta x=\sqrt{\frac{2*8600}{5700}}

Calculating:

\displaystyle \Delta x=\sqrt{3.0175}

\boxed{\displaystyle \Delta x=1.74\ m}

6 0
3 years ago
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