Answer:
V = 50 volts
Explanation:
Given that,
Resistance, R = 10 ohms
Current, I = 5 A
We need to find the potential difference across the circuit. We know that,
V = IR
Put all the values,
V = 5 × 10
V = 50 volts
Hence, the potential difference is equal to 50 volts.
Answer: C) The two particles will move away from each other
Explanation:
When two electrically charged bodies come closer, appears a force that attracts or repels them, depending on the sign of the charges of this two bodies.
This is stated by Coulomb's Law:
"The electrostatic force
between two point charges
and
is proportional to the product of the charges and inversely proportional to the square of the distance
that separates them, and has the direction of the line that joins them"
Mathematically this law is written as:
Where
is a proportionality constant.
Now, if
and
have the same sign charge (both positive or both negative), a repulsive force will act on these charges.
The resistance of the cylindrical wire is
.
Here
is the resistance,
is the length of the wire and
is the area of
cross section. Since the wire is cylindrical
.
Comparing two wires,

Dividing the above 2 equations,

Since 
The above ratio is

We also have,

The current through the Silver wire will be 4.23 times the current through the original wire.
I would say B. hope it helps
Answer: 
Explanation:
Given
Mass 
Spring constant 
Compression in the spring 
When the mass leaves the spring, the elastic potential energy of spring is being converted into kinetic energy of mass i.e.

The kinetic energy of the mass is 1.102 J.