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2 years ago

3 A picture is supported by two vertical strings; if the weighi

Physics

1 answer:

andrezito [222]2 years ago

7 0

Answer:

<em>The force exerted by each string is 25 N</em>

Explanation:

<u>Net Force</u>

The net force is the vector sum of forces acting on a body. The net force is a single force that represents the effect of the original forces on the body's motion. It gives the particle the same acceleration as all those actual forces together as described by Newton's second law of motion.

The picture described in the problem is hanging at rest supported by two vertical strings. This means that the net force acting on it is zero.

Assume the magnitude of each of these equal forces is F, and the picture has a weight of W=50 N, thus the net force is:

F + F - W

The positive signs indicate an upwards direction and the negative sign means a downwards direction. Since the net force is zero:

F + F - W = 0

2F = W

F = W/2 = 50 N/2

F = 25 N

The force exerted by each string is 25 N

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jenyasd209 [6]

Answer:

Image distance of apple=-6.7 cm

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Explanation:

We are given that an apple is placed 20.cm in front of a diverging lens.

Object distance=u=-20 cm

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Because focal length of diverging lens is negative.

We have to find the image distance and magnification of the apple.

Lens formula

$\frac{1}{f}=\frac{1}{v}-\frac{1}{u}$

Substitute the values then we get

$-\frac{1}{10}=\frac{1}{v}+\frac{1}{20}$

$\frac{1}{v}=-\frac{1}{10}-\frac{1}{20}$

$\frac{1}{v}=\frac{-2-1}{20}=-\frac{3}{20}$

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Image distance of apple=-6.7 cm

Magnification=m= $\frac{v}{u}=\frac{-\frac{20}{3}}{-20}$

Magnification of apple= $\frac{1}{3}=0.33$

Hence, the magnification of apple=0.33

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2 years ago

A wave with a frequency of 14 Hz has a wavelength of 7m. At what speed will this wave travel?

frutty [35]

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2 years ago

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valentina_108 [34]

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3 years ago

A wave has a wave length of 20mm and a frequency of 5 hertz. What is the speed?

zmey [24]

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2 years ago

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