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3 years ago

A razorblade manufacturer wants to test responses to a new blade for heavy beards. What is the best sample for an experiment?

Mathematics

2 answers:

myrzilka [38]3 years ago

7 0

Answer:

Step-by-step explanation:

Keith_Richards [23]3 years ago

5 0

The right answer would be A random sample of men who shave andn have heavy beard because the person should like to shave because you shouldn't force them to try it. They also need to have a heavy beard because the manufacturer is creating a razor blade for men with heavy beards. Hope this helps.

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jolli1 [7]

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4 years ago

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Researchers wanted to determine if having a supply of sugary snacks in the bedroom is associated with obesity. The researchers a

I am Lyosha [343]

Answer:

Step-by-step explanation:

The definition of an observational study is: one where researchers observe the effect of a risk factor or an intervention but they do not try to change who is exposed to the factor.

In this particular example, the researchers administered a questionnaire to 391 twelve-year-old and concluded that the body mass index of the adolescents who had a supply of sugary snacks in their bedroom was significantly higher than that of the adolescents who did not have a supply of sugary snacks in their bedroom.

This is not an observational study because the researchers actually administered a questionnaire and analyzed the results. To be an observational study the individuals would have been observed without any intervention (the questionnaire could have had an effect on the adolescents changing their habits)

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3 years ago

Find the length of the missing side. Leave your answer in simplest radical form.

Rainbow [258]

Answer:

Step-by-step explanation:

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3 years ago

Who created multiplication ?

Anuta_ua [19.1K]

Multiplication is a very old concept in math. So old that it dates back to ancient egypt, mesopotamia, etc. Each place probably came up with the concept on their own parallel to one another, or trade helped make the concept spread. It's very likely that the actual person who came up with the idea is unknown and won't be known since the concept is so ancient. It's like asking "who came up with the alphabet" which is an equally old concept.

Side note: multiplication is repeated addition. So if we added 3+3+3+3+3 to get 15, then we can say 3*5 = 12 as a shortcut. So its likely ancient peoples were adding the same number to itself over and over, leading them to develop a shortcut notation/method to get the answer quicker.

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4 years ago

The spread of a virus is modeled by V (t) = −t 3 + t 2 + 12t,

VashaNatasha [74]

Functions can be used to model real life scenarios

The reasonable domain is $\mathbf{[0,\infty)}$ .
The average rate of change from t = 0 to 2 is 20 persons per week
The instantaneous rate of change is $\mathbf{V'(t) = -3t^2 + 2t + 12}$ .
The slope of the tangent line at point (2,V(20) is 10
The rate of infection at the maximum point is 8.79 people per week

The function is given as:

$\mathbf{V(t) = -t^3 + t^2 + 12t}$

(a) Sketch V(t)

See attachment for the graph of $\mathbf{V(t) = -t^3 + t^2 + 12t}$

(b) The reasonable domain

t represents the number of weeks.

This means that: t cannot be negative.

So, the reasonable domain is: $\mathbf{[0,\infty)}$

(c) Average rate of change from t = 0 to 2

This is calculated as:

$\mathbf{m = \frac{V(a) - V(b)}{a - b}}$

So, we have:

$\mathbf{m = \frac{V(2) - V(0)}{2 - 0}}$

$\mathbf{m = \frac{V(2) - V(0)}{2}}$

Calculate V(2) and V(0)

$\mathbf{V(2) = (-2)^3 + (2)^2 + 12 \times 2 = 20}$

$\mathbf{V(0) = (0)^3 + (0)^2 + 12 \times 0 = 0}$

So, we have:

$\mathbf{m = \frac{20 - 0}{2}}$

$\mathbf{m = \frac{20}{2}}$

$\mathbf{m = 10}$

Hence, the average rate of change from t = 0 to 2 is 20

(d) The instantaneous rate of change using limits

$\mathbf{V(t) = -t^3 + t^2 + 12t}$

The instantaneous rate of change is calculated as:

$\mathbf{V'(t) = \lim_{h \to \infty} \frac{V(t + h) - V(t)}{h}}$

So, we have:

$\mathbf{V(t + h) = (-(t + h))^3 + (t + h)^2 + 12(t + h)}$

$\mathbf{V(t + h) = (-t - h)^3 + (t + h)^2 + 12(t + h)}$

Expand

$\mathbf{V(t + h) = (-t)^3 +3(-t)^2(-h) +3(-t)(-h)^2 + (-h)^3 + t^2 + 2th+ h^2 + 12t + 12h}$ $\mathbf{V(t + h) = -t^3 -3t^2h -3th^2 - h^3 + t^2 + 2th+ h^2 + 12t + 12h}$