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Afina-wow [57]
3 years ago
5

There are 15 animals in a barn. These animals are horses and chickens. There are 44 legs in all. Write a system of equations tha

t represents the situation and find out how many animals were horses and how many were chickens?
Mathematics
1 answer:
olganol [36]3 years ago
5 0

Answer:

7 horses and 8 chickens

Step-by-step explanation:

To solve this, first you would need to list out all of the available ratios. Then, find out how many legs are in each option.:

14 horses and 1 chicken = 58 legs

13 horses and 2 chickens = 56 legs

12 horses  and 3 chickens = etc.

11 horses and 4 chickens

10 horses and 5 chickens

9 horses and 6 chickens

8 horses and 7 chickens

7 horses and 8 chickens = 44 legs!

6 horses and 9 chickens

5 horses and 10 chickens

4 horses and 11 chickens

3 horses and 12 chickens

2 horses and 13 chickens

1 horses and 14 chickens

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Aleks [24]

Answer:

I think 21

Step-by-step explanation:

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Use point-slope form to write the equation of a line that passes through the point
Ymorist [56]

Answer:

y= -2x-22.

Step-by-step explanation:

1) the slope-interception common form is y=s*x+i, where 's' and 'i' are the slope and interception, unknown numbers;

2) if x₁= -3; y₁= -16, and s=-2, then the equation of the required line can be written in the point-interception form y-y₁=s(x-x₁); ⇔ y+16= -2(x+3);

3) the required equation in slope-interception form is:

y+16= -2x-6; ⇒ y= -2x-22.

note, the provided solution is not the only and shortest way.

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2 years ago
If p → q is true, then ~ p → ~ q is __________ true. always sometimes never
Yuliya22 [10]

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6 0
3 years ago
Activity
hodyreva [135]

Answer:

The answers to each part are:

Part A.

  • <u>The quantity of apples is one-third of the quantity of grapes</u>.

Part B.

  • <u>The quantity of apples is a quarter of the quantity of strawberries</u>.

Part C.

  • <u>The number of cherries is two-elevenths of the total fruit</u>.

Step-by-step explanation:

To identify the answer in each case, you must remember that all the parts are equal, then:

Part A.

The parts of apples are 1 and the parts grapes are 3, so if you divide the first quantity with the second quantity you obtain:

  • 1 / 3 = 1/3 (one-third)

So, <u>the quantity of apples is one-third of the quantity of grapes</u> or the quantity of apples is three times smaller than the quantity of grapes.

Part B.

The parts of apples are 1 and the parts of strawberries are 4, then you must divide the first quantity with the second quantity:

  • 1 / 4 = 1/4 (a quarter)

In this case, <u>the quantity of apples is a quarter of the quantity of strawberries</u> or the quantity of apples is four times smaller than the quantity of strawberries.

Part C.

First, you must add all the part of fruit:

  • <em>1 part apple</em>
  • <em>1 part orange</em>
  • <em>4 parts strawberry</em>
  • <em>2 parts cherry </em>
  • <em>3 parts grape</em>

The total of fruits is 11 parts, taking into account the quantity of cherries is 2, now you can divide the number of cherries with the total parts of fruit:

  • 2 / 11 = 2/11 (two-elevenths)

Now, you can see <u>the number of cherries is two-elevenths of the total fruit</u>.

3 0
3 years ago
A dog walker charges a flat rate of $6 per walk plus an hourly rate of $30. How much does the dog walkercharge for a 45 minute w
leonid [27]

hello

from the question given, the dog walker charges a flat rate of $6 and an extra $30 per hour.

we can write out an equation in function notation

let the number of hours be represented by x

f(x)=6+30x

now we can proceed to solve the cost of the walk for 45 minutes

\begin{gathered} 1hr=60\min s \\ \text{xhr}=45\min s \\ x=\frac{45}{60} \\ x=\frac{3}{4} \\ \text{therefore 45mins = 3/4 hours} \end{gathered}

now we can input the value into the equation and know the cost for 45 minutes walk

\begin{gathered} f(x)=6+30x \\ x=\frac{3}{4} \\ f(x)=6+30(\frac{3}{4}) \\ f(x)=6+22.5 \\ f(x)=28.5 \end{gathered}

from the calculation above, the cost of 45 minutes walk will cost $28.5

6 0
1 year ago
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