The steps to construct a regular hexagon inscribed in a circle using a compass and straightedge are given as follows:
1. <span>Construct a circle with its center at point H.
2. </span><span>Construct horizontal line l and point H on line l
3. </span>Label
the point of intersection of the circle and line l to the left of point
H, point J, and label the point of intersection of the circle and line l
to the right of point H, point K.<span>
4. Construct
a circle with its center at point J and having radius HJ .
Construct a circle with its center at point K having radius HJ
5. </span><span>Label
the point of intersection of circles H and J that lies above line l,
point M, and the point of their intersection that lies below line l,
point N. Label the point of intersection of circles H and K that lies
above line l, point O, and the point of their intersection that lies
below line l, point P.
6. </span><span>Construct and JM⎯⎯⎯⎯⎯, MO⎯⎯⎯⎯⎯⎯⎯, OK⎯⎯⎯⎯⎯⎯⎯, KP⎯⎯⎯⎯⎯, PN⎯⎯⎯⎯⎯⎯, and NJ⎯⎯⎯⎯⎯ to complete regular hexagon JMOKPN .</span>
Answer:5
Step-by-step explanation:
Answer:
10m/7
Step-by-step explanation:
quotient means division so 10 times m is 10m
and then we will divide 10m and 7
10m/7
please mark as brainliest
I think it’s b
Not for sure but it makes the most sense
X² + 3x = 10
Convert to standard form.
x² + 3x - 10 = 0
factor x² = x * x
factor -10 = 5 * -2
(x + 5) (x - 2) = 0
x(x -2) + 5(x-2) = 0
x² - 2x + 5x - 10 = 0
x² + 3x - 10 = 0
x + 5 = 0 x² + 3x = 10
x = -5 -5² + 3(-5) = 10
25 - 15 = 10
10 = 10
x - 2 = 0 x² + 3x = 10
x = 2 2² + 3(2) = 10
4 + 6 = 10
10 = 10
