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Jlenok [28]
3 years ago
15

3.00 moles of nitrogen and 4.00 moles of oxygen are placed in a 35.0 L container at a temperature of 298 K. What is the pressure

of the resulting mixture of gases?
A. 345 kPa
B. 395 kPa
C. 445 kPa
D. 495 kPa
Chemistry
1 answer:
Leto [7]3 years ago
7 0

Answer:

i think the answer is c hoped this helped

Explanation:

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The independent variable would be the type of liquid the dependen is the evaporation rates
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Are there a mole of golf in a 200 g gold necklace
meriva

Explanation:

The answer is 0.5 moles of gold

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Which is larger, an atom or a molecule??
skad [1K]
A molecule is larger because it is a bond of atoms.
3 0
3 years ago
2. Write the formula or name for the following
Tems11 [23]

Answer:

Diphosphorus pentoxide

Carbon dichloride

BCl3

N2H4

Explanation:

These are all covalent compounds. To name covalent compounds, you add prefixes to the beginning of their names depending on what the subscript is of each element. The prefixes are:

1: Mono

2: Di

3: Tri

4: Tetra

5: Penta

6: Hexa

7: Hepta

8: Octa

9: Nona

10: Deca

For example, since the first one is Phopsphorus with a 2 next to it, you add the prefix Di to it.

If the first element in the compound only has one, meaning no number next to it, you do not say mono. This is why we just say "Carbon" for the second one instead of "Monocarbon."

Finally, you always have to end the second element in the compound with "ide." So, "chlorine" becomes "chloride," "oxygen" becomes "oxide," and so on.

7 0
4 years ago
Experiments with rats show that if rats are dosed with 3.0 mg/kg of cocaine (that is, 3.0 mg cocaine per kg of animal mass), the
Aliun [14]

Answer:

The molecules of dopamine would be produced in a rat after 60 seconds of a 3.0 mg/kg dose of cocaine is 2.258\times 10^{12} molecules.

Explanation:

Concentration of dopamine = 0.75 μM = 7.5\times 10^{-7} M

1 μM  = 10^{-6} M

Volume of the brain in which dopamine is produced = V=5.00 mm^3

1 mm^3=10^{-6} L

V = 5.00\times 10^{-6} L

Moles of dopamine = n

Concentration=\frac{moles}{Volume}

7.5\times 10^{-7} M=\frac{n}{5.00\times 10^{-6} L}

n=7.5\times 10^{-7} M\times 5.00\times 10^{-6} L=3.75\times 10^{-12} mol

1 mol = 6.022\times 10^{23} molecules

So, molecules in 3.75\times 10^{-12} mol of dopamine :

3.75\times 10^{-12}\times 6.022\times 10^{23}=2.258\times 10^{12} molecules

4 0
3 years ago
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