Answer:
A is the answer because the must evaluate result
Answer:
make reclamation compulsory after bauxite has been removed
Explanation:
Available options:
<em>choose other infertile and uninhabited locations for bauxite mining
</em>
<em>
allow agriculture and mining to take place simultaneously in the location
</em>
<em>
ask farmers in the location to help in mining bauxite
</em>
<em>
make reclamation compulsory after bauxite has been removed</em>
The correct option and the best plan to solve the problem of permanent dislocation of farmers would be to make reclamation compulsory after the bauxite has been removed.
Reclamation would involve restoring the agricultural land back to its original status prior to the commencement of bauxite mining. By doing this, the farmers can return to their farmland after being temporarily displaced due to the mining activities.
The molecular weight of SOCL2 is 118.97 g/mol
The fourth group of the periodic table contains the elements from the carbon family. The element in the first period of the group is carbon, with atomic number 6. Then, in the second period, the element present is silicon, which is the one under consideration.
The symbol of silicon is:
²⁸Si₁₄
Answer:
116 years
Explanation:
To solve this, we will use the half life equation;
A(t) = A_o(½)^(t/t_½)
Where;
A(t) is the amount of strontium left after t years;
A_o is the initial quantity of strontium that will undergo decay;
t_½ is the half-life of strontium
t is the time it will take to decay
We are given;
A(t) = 7.5 g
A_o = 120 g
From online values, half life of strontium-90 is 29 years. Thus, t_½ = 29
Thus;
7.5 = 120 × ½^(t/29)
Divide both sides by 120 to get;
7.5/120 = ½^(t/29)
0.0625 = ½^(t/29)
In 0.0625 = (t/29) In ½
-2.772589 = (t/29) × (-0.693147)
(t/29) = -2.772589/(-0.693147)
t/29 = 4
t = 29 × 4
t = 116 years
