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Grace [21]
3 years ago
6

What information is given by the superscripts in an electron configuration?

Chemistry
1 answer:
Paraphin [41]3 years ago
8 0
<span>The superscripts in an electron configuration represents the number of electrons and protons in an element. </span>
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A. 207 kJ<br> B. 4730 kJ<br> O C. 9460 kJ<br> O D. 414 kJ
slavikrds [6]

Answer:

C = 9460 Kj

Explanation:

Given data:

Mass of copper = 2kg

Latent heat of vaporization = 4730 Kj/Kg

Energy required to vaporize 2kg copper = ?

Solution:

Equation

Q= mLvap

by putting values,

Q= 2kg ×  4730 Kj/Kg

Q = 9460 Kj

3 0
3 years ago
3- AR 385-63/MCO 3570.1C is used in conjunction with
Rasek [7]
AR 385-63/MCO 3570.1C is used in conjunction with DA PAM 385-63.
AR 385-63/MCO 3570.1C is the regulation or order which provides revised range safety policy for the Army and Marine Corps.
This order/regulation applies on the Active Army or the Army National Guard of the United states.
8 0
2 years ago
What is the length of an average solar cycle? A. 5 years B. 11 years C. 22 years D. 10 years
Tems11 [23]
B. A solar cycle usually lasts 11 years.
4 0
2 years ago
Smoke filling up a room is diffusion or not
maxonik [38]
Yes, because it comes from a one thing and spreads throughout the entire space. Similar to dripping foot coloring into a glass of water, or spraying air freshener.
7 0
3 years ago
If the freezing point of the solution had been incorrectly read 0.3 °C lower than the true freezing point, would the calculated
Dovator [93]

Answer : The molar mass of the solute would be low.

Explanation :

Formula used for depression in freezing point is:  

\Delta T_f=i\times K_f\times m\\\\T^o-T_s=i\times K_f\times\frac{w_b}{M_b}\times w_a}

where,

\Delta T_f = change in freezing point

\Delta T_s = freezing point of solution

\Delta T^o = freezing point of water

i = Van't Hoff factor

K_f = freezing point constant

m = molality

w_b = mass of solute

w_a = mass of solvent

M_b = molar mass of solute

From the formula we conclude that, when the freezing point of the solution read incorrectly that is freezing point of the solution is lower than the true freezing point then this means that change in freezing point would be high and the molar mass of the solute would be low.

Hence, the molar mass of the solute would be low.

6 0
3 years ago
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