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aleksandr82 [10.1K]
3 years ago
9

How do scientsts determine is a newly found thing is dead or alive.

Chemistry
1 answer:
butalik [34]3 years ago
4 0

The substance is dead or alive is determined by response or consciousness of the substance to external stimulus.

<h3><u>Explanation</u>:</h3>

The living organisms do have several characteristics. They are growth, reproduction, consciousness etc. But among them, consciousness is the only feature that's confined within only the living world. No non living things have this feature.

So if the scientist can find that the substance found have some response to external stimulus, then it does have life. And if it doesn't response to any sort of external stimulus, then it doesn't have life.

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Problem PageQuestion The airbags that protect people in car crashes are inflated by the extremely rapid decomposition of sodium
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Answer:

1. 2NaN₃(s) → 2Na(s) + 3N₂(g)

2. 14.5 g NaN₃

Explanation:

The answer is incomplete, as it is missing the required values to solve the problem. An internet search shows me these values for this question. Keep in mind that if your values are different your result will be different as well, but the solving methodology won't change.

" The airbags that protect people in car crashes are inflated by the extremely rapid decomposition of sodium azide, which produces large volumes of nitrogen gas. 1. Write a balanced chemical equation, including physical state symbols, for the decomposition of solid sodium azide (NaN₃) into solid sodium and gaseous dinitrogen. 2. Suppose 71.0 L of dinitrogen gas are produced by this reaction, at a temperature of 16.0 °C and pressure of exactly 1 atm. Calculate the mass of sodium azide that must have reacted. Round your answer to 3 significant digits. "

1. The <u>reaction that takes place is</u>:

  • 2NaN₃(s) → 2Na(s) + 3N₂(g)

2. We use PV=nRT to <u>calculate the moles of N₂ that were produced</u>.

P = 1 atm

V = 71.0 L

n = ?

T = 16.0 °C ⇒ 16.0 + 273.16 = 289.16 K

  • 1 atm * 71.0 L = n * 0.082 atm·L·mol⁻¹·K⁻¹ * 289.16 K
  • n = 0.334 mol

Now we <u>convert N₂ moles to NaN₃ moles</u>:

  • 0.334 mol N₂ * \frac{2molNaN_{3}}{3molN_2} = 0.223 mol NaN₃

Finally we <u>convert NaN₃ moles to grams</u>, using its molar mass:

  • 0.223 mol NaN₃ * 65 g/mol = 14.5 g NaN₃

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