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bogdanovich [222]

4 years ago

13

Identify a process that is NOT reversible. A. melting of steel B. freezing water C. melting of ice D. frying an egg E. depositio

n of carbon dioxide (gas to solid)

1 answer:

vredina [299]4 years ago

8 0

I’m pretty sure it would be D. Frying an egg

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Helppp , I’ll give Brainly

PIT_PIT [208]

C , the potential energy of a 500kg boulder

8 0

3 years ago

Your lab partner accidentally spills some acid on his wrist and watchband. You should: (Check all that apply.)

nordsb [41]

Answer: Remove the watch and watchband immediately, and rinse his wrist for at least 15 minutes to be sure all hazardous material has been washed away. Let the TA inspect his wrist to see if it is okay.

Explanation:

The question is incomplete, the choices are:

a. Take him to the safety shower, and make sure he stands under it for at least 15 minutes to be sure all hazardous material has been washed away. b. Remove the watch and watchband immediately, and rinse his wrist for at least 15 minutes to be sure all hazardous material has been washed away. c. Let the TA inspect his wrist to see if it is okay.

d. Rinse the watch band before allowing him to put it back on.

An acid is traditionally considered to be any chemical compound that, when dissolved in water, produces a solution with greater hydronium cation activity than pure water, i.e., a pH less than 7. Both corrosive acids (and also corrosive bases) <u>are capable of destroying skin</u> by catalyzing the hydrolysis of fats, which are chemically esters. Also, when acids attack metals, hydrogen gas is often released.

This is why your lab partner should remove the watch and watchband immediately, and rinse his wrist for at least 15 minutes to be sure all hazardous material has been washed away. This ensures that the acid is can not damage the skin. And also the person should make sure that someone qualified checks it to see if it is okay.

7 0

3 years ago

You want to make 500 ml of a 1 N solution of sulfuric acid (H2SO4, MW: 98.1). How many grams of sulfuric acid do you need?

umka21 [38]

Answer:

24.525 g of sulfuric acid.

Explanation:

Hello,

Normality (units of eq/L) is defined as:

$N=\frac{eq_{solute}}{V_{solution}}$

Since the sulfuric acid is the solute, and we already have the volume of the solution (500 mL) but we need it in liters (0.5 L, just divide into 1000), the equivalent grams of solute are given by:

$eq_{solute}=N*V_{solution}=1\frac{eq}{L}*0.5L=0.5 eq$

Now, since the sulfuric acid is diprotic (2 hydrogen atoms in its formula) 1 mole of sulfuric acid has 2 equivalent grams of sulfuric acid, so the mole-mass relationship is developed to find its required mass as follows:

$m_{H_2SO_4}=0.5eqH_2SO_4(\frac{1molH_2SO_4}{2 eqH_2SO_4}) (\frac{98.1 g H_2SO_4}{1 mol H_2SO_4} )\\m_{H_2SO_4}=24.525 g H_2SO_4$

Best regards.

4 0

4 years ago

List 4 physical properties of each of the following:

Bogdan [553]

A piece of paper is thin, slighlty smooth, can be white and smells woody. 500 g of butter has a density of 0.911 g/ml and has a volume thus of 548.85 ml. Butter has a color yellow and smells fatty. A glass of milk has a white color, sour smell and taste and the milk occupies the volume of glass. Candle is waxy, can be long or short, can have colors of different varieties and is cylindrical.

3 0

3 years ago

The total volume of seawater is 1.5 x 10²¹ L. Seawater contains approximately 3.5% sodium chloride by mass. At that high of a co

garri49 [273]

Answer:

There are $5.408\times 10^{22}$ grams contained in all the seawater in the world.

Explanation:

At first let is determinate the total mass of seawater ( $m_{sw}$ ), measured in grams, in the world by definition of density and considering that mass is distributed uniformly:

$m_{sw} = \rho_{sw}\cdot V_{sw}$

Where:

$\rho_{sw}$ - Density of seawater, measured in grams per liters.

$V_{sw}$ - Volume of seawater, measured in liters.

If $V_{sw} = 1.5\times 10^{21}\,L$ and $\rho_{sw} = 1030\,\frac{g}{L}$ , then:

$m_{sw}=\left(1030\,\frac{g}{L} \right)\cdot (1.5\times 10^{21}\,L)$

$m_{sw} = 1.545\times 10^{24}\,g$

The total mass of sodium chloride is determined by the following ratio:

$r = \frac{m_{NaCl}}{m_{sw}}$

$m_{NaCl} = r\cdot m_{sw}$

Given that $m_{sw} = 1.545\times 10^{24}\,g$ and $r = 0.035$ , the total mass of sodium chloride in all the seawater in the world is:

$m_{NaCl} = 0.035\cdot (1.545\times 10^{24}\,g)$

$m_{NaCl} = 5.408\times 10^{22}\,g$

There are $5.408\times 10^{22}$ grams contained in all the seawater in the world.

8 0

4 years ago