Question

A number is equal to twice a smaller number plus 3. Yhe same number is equal to twice the sum of smaller number and 1. How many soluyions are possible for this situation

Answer 1

Answer:

There is no solution to the problem

Step-by-step explanation:

In order to find the solutions to the problem you can write the situation in an algebraic form.

You have that a number is equal to twice a smaller number plus 3. This can be written as follow:

$x=2y+3$      (1)

where x is the number and y is the smaller number

Furthermore, the same number x is equal to twice the sum of the smaller number and 1, which can be written as follow:

$x=2(y+1)$     (2)

To find the solution you equal the equation (1) with (2), and you solve for y:

$2y+3=2y+1$

$3=1$

You obtain an inconsistency, hence, the situation of the problem does not have solution