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Dimas [21]
3 years ago
12

A number is equal to twice a smaller number plus 3. Yhe same number is equal to twice the sum of smaller number and 1. How many

soluyions are possible for this situation
Mathematics
1 answer:
allsm [11]3 years ago
5 0

Answer:

There is no solution to the problem

Step-by-step explanation:

In order to find the solutions to the problem you can write the situation in an algebraic form.

You have that a number is equal to twice a smaller number plus 3. This can be written as follow:

x=2y+3      (1)

where x is the number and y is the smaller number

Furthermore, the same number x is equal to twice the sum of the smaller number and 1, which can be written as follow:

x=2(y+1)     (2)

To find the solution you equal the equation (1) with (2), and you solve for y:

2y+3=2y+1

3=1

You obtain an inconsistency, hence, the situation of the problem does not have solution

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