Which element is reduced in this reaction? cr2o72−+3hno2+5h+→2cr3++3no3−+4h2o enter the chemical symbol of the element?

1 answer:

3 0

<span>A reducing agent loses electrons, so on the left side of the equation N in HNO2 has an oxidation number of +3 and on the right side in NO3^- it has an oxidation number of +5, so it has lost electrons. Thus, the reducing agent would be HNO2.</span>

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