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forsale [732]
3 years ago
5

Is ammonium ion a bronsted base

Chemistry
1 answer:
Leokris [45]3 years ago
6 0

Unlikely. It's unlikely for ammonium ion {\text{NH}_4}^{+} to accept a proton \text{H}^{+} and act as a Bronsted-Lowry Acid.

<h3>Explanation</h3>

What's the definition of Bronsted-Lowry acids and bases?

  • Bronsted-Lowry Acid: a species that can donate one or more protons \text{H}^{+} in a reaction.
  • Bronsted-Lowry Base: a species that can accept one or more protons \text{H}^{+}

Ammonium ions {\text{NH}_4}^{+} are positive. Protons \text{H}^{+} are also positive.

Positive charges repel each other, which means that it will be difficult for {\text{NH}_4}^{+} to accept any additional protons. As a result, it's unlikely that {\text{NH}_4}^{+} will accept <em>any</em> proton and act like a Bronsted-Lowry Base.

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Convert 2.072x10^43 atoms element to moles
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Given :

Number of atoms of an element, n = 2.072 × 10⁴³ atoms.

To Find :

Number of moles of that element in given number of atoms.

Solution :

We know, 1 mole of any element contains 6.022 × 10²³ atoms.

So, number of moles in given number of atoms are :

n = \dfrac{2.072\times 10^{43}}{6.022\times 10^{23}}\\\\n = 3.441 \times 10^{19}\ moles

Hence, this is the required solution.

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3 years ago
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Elements in the same group have _____. the same number of electron shells the same atomic number similar chemical properties the
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Displacement is called vector quantity. Why?
Irina18 [472]

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3 years ago
What is the ph of a solution which is 0. 023 m in weak base and 0. 037 m in the conjugate weak acid ( a = 7. 1 × 10^−6)?
Rzqust [24]

The pH of a solution which is 0.023 m in weak base and 0 037 m in the conjugate weak acid whose Ka= 7.1 × 10⁻⁶ is 4.93.

pH determines the amount of hydrogen and hydroxide ions in a solution. It is the negative logarithm of hydrogen ion concentration.

Given,

Ka= 7.1 × 10⁻⁶

Weak base = 0.023M

Acid = 0.037M

Using base dissociation constant, Ka we can calculate pKa by:

pKa = -log [Ka]

pKa = -log [7.1 × 10⁻⁶]

pKa = 5.15

A weak base and its conjugate acid are present in equal proportions in buffer solution. Using the Henderson-Hasselbalch equation, we can find out the pH of a buffer solution that constitutes a weak base and its conjugate acid.

Using Henderson-Hasselbalch equation,

pH = pKa + log [Weak base / acid]

pH = 5.15 + log [0.023 / 0.037]

pH = 5.15 + log[0.6]

pH = 5.15 - 0.22

pH = 4.93

Therefore, the pH of the solution is 4.93.

Learn more about pH here, brainly.com/question/22390063

#SPJ4

     

   

5 0
2 years ago
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