Answer:
Determine the location of the lost significant place value by placing a bar over the digit.
Explanation:
Hydrophobic in simple terms is the "fear" of water.
In chemistry, Ionic salts are technically hydrophilic as they will dissolve in water.
most fats and oils or triesters won't why?
salts are made from ions and their structure contain polar bonds Na+ and Cl-
Fats and oils tend to not have these.
Fats and oils contain many carbon covalent bonds which are non-polar which tend to make the molecule non-polar as a whole, therefore, it can't dissolve in water and is said to be hydrophobic.
Hope that heps :)
NB included a diagram to help.
mass of pentane : = 30.303 g
moles of Al₂(CO₃)₃ : = 0.147
<h3>Further explanation</h3>
Given
1. Reaction
C₅H₁₂+8O₂→6H₂O+5CO₂.
45.3 g water
2. 2AlCl₃ + 3MgCO₃ → Al₂(CO₃)₃ + 3MgCl₂
37.2 MgCO₃
Required
mass of pentane
moles of Al₂(CO₃)₃
Solution
1. mol water = 45.3 : 18 g/mol = 2.52
From equation, mol ratio of C₅H₁₂ : H₂O = 1 : 6, so mol pentane :
= 1/6 x mol H₂O
= 1/6 x 2.52
= 0.42
Mass pentane :
= mol x MW
= 0.42 x 72.15 g/mol
= 30.303 g
2. mol MgCO₃ : 37.2 : 84,3139 g/mol = 0.44
mol Al₂(CO₃)₃ :
= 1/3 x mol MgCO₃
= 1/3 x 0.44
= 0.147
Answer:
El cocodrilo se arrastró durante 20.833 segundos.
Explanation:
El enunciado presenta omisiones y errores conceptuales. La forma correcta es la siguiente: <em>"Un cocodrilo se arrastró 25 metros hacia la derecha con una rapidez promedio de 1.2 metros por segundo. ¿Cuántos segundos se arrastró el cocodrilo?"</em>
Consideremos que el cocodrilo tiene un movimiento rectilíneo uniforme, el tiempo requerido para el recorrido se calcula con la siguiente ecuación cinemática:
(1)
Donde:
- Distancia recorrida, en metros.
- Rapidez del cocodrilo, en metros por segundo.
- Tiempo, en segundos.
Si
y
, entonces el tiempo empleado por el cocodrilo es:


El cocodrilo se arrastró durante 20.833 segundos.
<em />
Guy-Lussac's Law states that the volume and the temperature are directly proportional given that the pressure remains constant.
For this problem, we will assume constant pressure. Based on the law:
(Volume/Temperatur)1 = (Volume/Temperature)2
(3.75/100) = (6.52/T)
T = 166.667 kelvin