Question

calculate the volume occupied by 10g of propane gas, under normal conditions of temperature and pressure

Answer 1

Answer:

5.5 L

Explanation:

First we convert 10 g of propane gas (C₃H₈) to moles, using its molar mass:

• 10 g ÷ 44 g/mol = 0.23 mol

Then we use the PV=nRT formula, where:

• P = 1 atm & T = 293 K (This are normal conditions of T and P)

• n = 0.23 mol

• R = 0.082 atm·L·mol⁻¹·K⁻¹

• V = ?

1 atm * V = 0.23 mol * 0.082 atm·L·mol⁻¹·K⁻¹ * 293 K

• V = 5.5 L