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Lerok [7]
3 years ago
8

Mrs ameldos class has 5 students with blue eyes 7 with brown eyes 4 with hazel eyes and 4 with green eyes. Two students are sele

cted at random. Whats the probability of two blue
Mathematics
2 answers:
IRINA_888 [86]3 years ago
8 0
If two blue;
5/20*4/19
=1/19
Ivan3 years ago
5 0
Hwy friend
Let's figure this out.
5+7+4+4= 20 total students
4/20 students have hazel eyes
6/20 students do not have hazel eyes
16 / 20 =.8
80% chance that 1 is not hazel
80% that the 2nd isn't hazel
To find the probability that both will not be hazel you must multiply:
80% by 80% (.8 * .8)
.8 *.8 = .64
There is a 64% chance both of the selected students wont have hazel eyes.  
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kvv77 [185]
\bf \begin{array}{ccccccccc}
&&x_1&&y_1&&x_2&&y_2\\
&A&(~ -3 &,& -4~) 
&P&(~ -1 &,& -\frac{12}{5}~)
\end{array}
\\\\\\
d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2}
\\\\\\
AP=\sqrt{[-1-(-3)]^2+[-\frac{12}{5}-(-4)]^2}
\\\\\\
AP=\sqrt{(-1+3)^2+(-\frac{12}{5}+4)^2}\implies AP=\sqrt{2^2+\left( \frac{8}{5} \right)^2}
\\\\\\
AP=\sqrt{4+\frac{64}{25}}\implies AP=\sqrt{\cfrac{164}{25}}\implies AP=\cfrac{\sqrt{164}}{\sqrt{25}}
\\\\\\
\boxed{AP=\cfrac{2\sqrt{41}}{5}}



\bf \begin{array}{ccccccccc}
&&x_1&&y_1&&x_2&&y_2\\
&P&(~ -1 &,& -\frac{12}{5}~) 
&B&(~ 2 &,& 0~)
\end{array}
\\\\\\
PB=\sqrt{[2-(-1)]^2+[0-\left(-\frac{12}{5}  \right)]^2}
\\\\\\
PB=\sqrt{(2+1)^2+\left( \frac{12}{5} \right)^2}\implies PB=\sqrt{9+\frac{144}{25}}\implies PB=\sqrt{\cfrac{369}{25}}
\\\\\\
PB=\cfrac{\sqrt{369}}{\sqrt{25}}\implies \boxed{PB=\cfrac{3\sqrt{41}}{5}}

so, let's check the ratio of AP:PB

\bf AP:PB\implies \cfrac{AP}{PB}\implies \cfrac{\frac{2\sqrt{41}}{5}}{\frac{3\sqrt{41}}{5}}\implies \cfrac{2\underline{\sqrt{41}}}{\underline{5}}\cdot \cfrac{\underline{5}}{3\underline{\sqrt{41}}}\implies \cfrac{2}{3}
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Step-by-step explanation:

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