The life expectancies of residents of a country for which the average annual income is $80,000 for the three models are 12309.9352, 172.2436 and 4828.1393

The life expectancies of the models are given as:

$y =69.9352 + 0.1530\times (income)$ --- model 1

$y =4.2436 + 0.0021\times (income)$ --- model 2

$y =4.1393 + 0.0603\times (income)$ --- model 3

Given that the average annual income is $80,000;

We simply substitute 80000 for income in the equations of the three models.

So, we have:

Model 1

$y =69.9352 + 0.1530\times (income)$

$y =69.9352 + 0.1530\times 80000$

$y =12309.9352$

Model 2

$y =4.2436 + 0.0021\times (income)$

$y =4.2436 + 0.0021\times 80000$

$y =172.2436$

Model 3

$y =4.1393 + 0.0603\times (income)$

$y =4.1393 + 0.0603\times 80000$

$y =4828.1393$

Hence, the life expectancies are 12309.9352, 172.2436 and 4828.1393

Read more about linear models at:

brainly.com/question/8609070

4 0

2 years ago

100 POINTS. ASAP. PLS HELP!

IgorC [24]

Answer:

12.81%

Step-by-step explanation:

2600-5500=20500

20500/16=1281.25

1281.25/100= 12.8125

rounded 12.81%

7 0

3 years ago

Read 2 more answers

PLEASE someone help me on this I would appreciate it.

Anton [14]

2x-y =3
multiply by 4
8x - 4y = 12
3x +4y = 10 (unchanged equation)
------------------add
11x = 22

answer is A. the first.
first equation multiplied by 4 then sum to get 11x = 22

3 0

3 years ago

Find the equation for the line of best fit using the two points that are close to the line of best fit (2,70) and (4.5, 90)

kari74 [83]

Given:

Two points that are close to the line of best fit are (2,70) and (4.5, 90).

To find:

Th equation of best fit line using the given two points.

Solution:

We know that, if a line passes through the two points, then the equation of line is

$y-y_1=\dfrac{y_2-y_1}{x_2-x_1}(x-x_1)$