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andrezito [222]
2 years ago
11

g Which of the following is TRUE for a system that is in dynamic equilibrium? Which of the following is TRUE for a system that i

s in dynamic equilibrium? The concentration of products is equal to the concentration of the reactants. The forward reaction goes to 100% completion. Both the forward and reverse reactions come to a halt. The reaction rate of the forward reaction approaches zero. none of the above
Chemistry
1 answer:
Firdavs [7]2 years ago
3 0

Answer:

none of the above

Explanation:

A system is said to have attained dynamic equilibrium when the forward and reverse reactions proceed at the same rate. That is;

Rate of forward reaction = Rate of reverse reaction

The implication of this is that the concentrations of reactants and products remain constant when dynamic equilibrium is attained in a system. This does not mean that the reactant and product concentrations become equal; it rather means that their concentrations do not significantly change once dynamic equilibrium has been attained.

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blagie [28]
The answer is:

1. 500g stainless steel cup 
<span>2. 500g aluminum cup </span>
<span>3. 750g aluminum cup</span>
8 0
3 years ago
What directions do periods go on a periodic table
labwork [276]

Answer:

left to right

7 0
3 years ago
Use the following half-reactions to construct a voltaic cell:
velikii [3]

<u>Answer:</u> The correct answer is 3Ag^+(aq.)+Cr(s)\rightarrow 3Ag(s)+Cr^{3+}(aq.);E^o_{cell}=+1.53V

<u>Explanation:</u>

We are given:

Cr^{3+}(aq.)+3e^-\rightarrow Cr(s);E^o=-0.73V\\\\Ag^+(aq.)+e^-\rightarrow Ag(s);E^o=+0.80V

The substance having highest positive E^o potential will always get reduced and will undergo reduction reaction. Here, silver will always undergo reduction reaction will get reduced.

Chromium will undergo oxidation reaction and will get oxidized.

The half reactions for the above cell is:

Oxidation half reaction: Cr(s)\rightarrow Cr^{3+}+3e^-;E^o_{Cr^{3+}/Cr}=-0.73V

Reduction half reaction: Ag^{+}+e^-\rightarrow Ag(s);E^o_{Ag^{+}/Ag}=0.80V       ( × 3)

Net equation:  3Ag^+(aq.)+Cr(s)\rightarrow 3Ag(s)+Cr^{3+}(aq.)

Oxidation reaction occurs at anode and reduction reaction occurs at cathode.

To calculate the E^o_{cell} of the reaction, we use the equation:

E^o_{cell}=E^o_{cathode}-E^o_{anode}

Putting values in above equation, we get:

E^o_{cell}=0.80-(-0.73)=1.53V

Hence, the correct answer is 3Ag^+(aq.)+Cr(s)\rightarrow 3Ag(s)+Cr^{3+}(aq.);E^o_{cell}=+1.53V

4 0
3 years ago
What form of waste cannot be recycled to make new products?
skelet666 [1.2K]
~Hello there! ^_^

Your question: What form of waste cannot be recycled to make new products..?

Your answer: Food is a form of waste that cannot be recycled to make new products.

Happy Studying! =)


4 0
3 years ago
Read 2 more answers
Determine the correct set-up below to determine what mass, in grams, of N2 is needed to completely react with 105 g F2 ?
neonofarm [45]

Answer:

C: 1 mol F2/38 g F2

Explanation:

The reaction equation is;

N2 + 3F2 = 2NF3

Now, to know how many grams, of N2 is needed to completely react with 105 g F2 and since the molar mass of N2 is 28.02 g/mol, Molar mass of F2 is 38 g/mol, number of moles attached to N2 and F2 in the reaction are 1 and 3 moles respectively, then we will have;

105 g F2 × 1 mol F2/38 g F2 × 1 mol N2/3 mol F2 × 28.02 g N2/1 mol N2

Option C is Thus correct

4 0
3 years ago
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